In theory, you can of course use any language you like, but there are a few commonly used ones.
From your list it would be c++ or c#, because if you actually have the interest long term then those will be the languages used by the various "big"/well known/used engines.
I would suggest c#, because it can be used with the Unity engine, which has an enormous community with help resources especially to start out and learn to program or game development.
On the other hand I would also suggest JavaScript. It isn't used for any of the big title development, but for all the *.io games like slither and so on. When looking at such games you will quickly notice that they are generally much simpler (for example 2D not 3D), because game engines are just simpler in JavaScript. While this is obviously limiting it might help to get something simple actually working, instead of getting stuck in extra complexities and additional features until you lose your motivation.
The basic programming you learn is still the same, so after you have learned a language you can quickly pick up most others.
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Answers:
1. D
2. A
3. B
4. C
Explanation: I just did it and got a 100%
1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
Answer:
Sedimentary Rocks
Explanation:
Sedimentary rocks are essentially the Frankenstein monsters of the rock world. They're made up of pieces of igneous and metamorphic rocks, sand, clay, and other sedimentary rocks.
