Answer:
nested loop
pls mark me as brainliest
I think it is probably carnival festival!
Answer:
<u>C program to find the sum of the series( 1/2 + 2/3 + ... + i/i+1)</u>
#include <stdio.h>
double m(int i);//function declaration
//driver function
int main() {
int i;
printf("Enter number of item in the series-\n");//Taking input from user
scanf("%d",&i);
double a= m(i);//Calling function
printf("sum=%lf",a);
return 0;
}
double m(int i)//Defining function
{
double j,k;
double sum=0;
for(j=1;j<i+1;j++)//Loop for the sum
{
k=j+1;
sum=sum+(j/k);
}
return sum;
}
<u>Output:</u>
Enter number of item in the series-5
sum=3.550000
Answer:
- Calculate the additional CPI due to the icache stalls.
- Calculate the additional CPI due to the dcache stalls.
- Calculate the overall CPI for the machine.
The additional CPI due to icache stalls = Hit Rate * Hit Latency + Miss Rate*
Miss Penalty = 0.9*2 + 0.1*50 = 1.8 + 5 = 6.8
The additional CPI due to dcache stalls = 0.92*2 + 0.08*124 = 11.76
The overall CPI = 0.3*11.76 + 0.7*1.0 + 1.0*6.8 = 11.03 7.
Explanation:
