Question

A particular type of cell increases by 75% in number every hour. Find the number of cells present at the end of 12 hours if there are initially 4 of these cells?

Answer 1

We have been given that a particular type of cell increases by 75% in number every hour. We are asked to find the number of cells present at the end of 12 hours if there are initially 4 of these cells.

We will use exponential growth formula to solve our given problem.

$y=a\cdot (1+r)^x$, where,

y = Final amount,

a = Initial amount,

r = Growth rate in decimal form,

x = Time.

$75\%=\frac{75}{100}=0.75$

Upon substituting initial value $a=4$ and $x=12$ in above formula, we will get:

$y=4\cdot (1+0.75)^{12}$

$y=4\cdot (1.75)^{12}$

$y=4\cdot 825.0050068497657776$

$y=3300.020027$

$y\approx 3300$

Therefore, there will be approximately 3300 cells at the end of 12 hours.