All categories

3 years ago

Round $45736.41995 to the nearest dollar

Mathematics

1 answer:

Sonja [21]3 years ago

4 0

$55736.41995

Sorry if its incorrect!!

You might be interested in

Please help and thank you!

bogdanovich [222]

the answer is 13 :))

4 0

3 years ago

Read 2 more answers

Choose all properties that were used to simplify the following problem:

ycow [4]

All minus the addition

4 0

4 years ago

Read 2 more answers

A rectangular prism has a length of 4cm, a height of 9cm, and a width of 16cm. What is its volume, in cubic cm?

Gre4nikov [31]

Answer: 432

Step-by-step explanation: 4 x 7 = 16

16 x 27 = 432

Hope this helps!

5 0

3 years ago

Please interact if you know the answer!

IRISSAK [1]

Answer:

Step-by-step explanation:

The supplementary angles to ∠x are adding to 180° and are ∠HGC and ∠BGA

If ∠DGE = 90° , then

∠CGD is also 90° because ∠DGE and ∠CGD are a linear pair and

∠HGC is also 90° because ∠DGE and ∠HGC are vertical angles

6 0

3 years ago

Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.

Arisa [49]

Answer: $S_n=5(1-\dfrac{1}{n+1})$ ; 5

Step-by-step explanation:

Given series : $[\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]$

Sum of series = $S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]$

Consider $\dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}$

$=\dfrac{1}{n}-\dfrac{1}{n+1}$

⇒ $S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]$

Put values of n= 1,2,3,4,5,.....n

⇒ $S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})$

All terms get cancel but First and last terms left behind.

⇒ $S_n=5(1-\dfrac{1}{n+1})$

Formula for the nth partial sum of the series :

$S_n=5(1-\dfrac{1}{n+1})$

Also, $\lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})$

$=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5$

4 0

3 years ago