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Korvikt [17]
3 years ago
10

You purchased 150 feet of chain that normally sells for 0.15 per inch you were charged 22.50 for the sale was the price correct

if not what is the correct price an what mistake was made
Mathematics
1 answer:
pav-90 [236]3 years ago
8 0
The appropriate price is
  (150 ft)*(($0.15/in)*(12 in/ft)) = $270.00

Apparently, the factor (12 in/ft) was left out of the computation, so the charge was for $0.15 per foot.


a) The price was not correct. The correct price was $270.00

b) The mistake was charging by the foot rather than by the inch.
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Answer:

It is already rounded to the nearest tenth! Hope this helps!

Step-by-step explanation:

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Please help! Thanks in advance.
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In this problem, we need to plug in the given x values for f(x)=0 and find a and b.

When we plug in 1, we get: 2 \times {1}^{4} - 5 \times {1}^{3} - 14 \times {1}^{2} + a \times 1 + b = 0

Simplify:
2 - 5 - 14 + a + b = 0
- 17 + a + b = 0
a + b = 17

We got our first statement about the values of the variables. If we find one more we can find those 2 variables.

We have another given root: 4.

Plug it in:
2 \times {4}^{4} - 5 \times {4}^{3} - 14 \times {4}^{2} + a \times 4 + b = 0
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Now we have our second one. We can combine them:
a + b = 17 \\ 4a + b = 32

I use elimination method which is easier here.

Multiply the top equation by -1: - a - b = - 17 \\ 4a + b = 32

Add them up:
3a = 15

Simplify:
a = 5

Now we have a, we can plug in one of those equations to find b:
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What is the answer for: 7 - 8(x-3)=x-14
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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

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<h3>1.</h3>

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is <em>reflection across line BC</em>.

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<h3>2.</h3>

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, <em>corresponding parts are coincident</em>. That is, vertex G' (the image of vertex G) will coincide with vertex A.

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<h3>3.</h3>

The markings on the figure show the corresponding parts to be ...

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And the reflexive property of congruence tells us BC corresponds to itself:

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SSS

  Corresponding sides are listed above. Here, we list them again:

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SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

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