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Thepotemich [5.8K]
4 years ago
15

How can I solve this system of equation with substitution 2a+2x=18 and a+3x=17

Mathematics
1 answer:
3241004551 [841]4 years ago
5 0
First solve for one variable
solve for a in second eqatn

minus 3x both sides
a=17-3x
sub 17-3x for a in first equaiton
2(17-3x)+2x=18
34-6x+2x=18
34-4x=18
minus 34 both sides
-4x=-16
divide both sides by -4
x=4
sub back
a=17-3x
a=17-3(4)
a=17-12
a=5

a is 5
x=4












WORK SECTION (without thoughts)
2a+2x=18 to a+x=9
a+3x=17

a=17-3x
(17-3x)+x=9
17-2x=9
-2x=-8
x=4

a=17-3(4)
a=17-12
a=5

x=4
a=5
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