The exact value of cos120 if the measure 120 degrees intersects the unit circle at point (-1/2,√3/2) is 0.5
<h3>Solving trigonometry identity</h3>
If an angle of measure 120 degrees intersects the unit circle at point (-1/2,√3/2), the measure of cos(120) can be expressed as;
Cos120 = cos(90 + 30)
Using the cosine rule of addition
cos(90 + 30) = cos90cos30 - sin90sin30
cos(90 + 30) = 0(√3/2) - 1(0.5)
cos(90 + 30) = 0 - 0.5
cos(90 + 30) = 0.5
Hence the exact value of cos120 if the measure 120 degrees intersects the unit circle at point (-1/2,√3/2) is 0.5
Learn more on unit circle here: brainly.com/question/23989157
#SPJ1
Answer:
y=-5/3x+20
Step-by-step explanation:
Let the equation of the required line be represented as ![\[y=mx+c\]](https://tex.z-dn.net/?f=%5C%5By%3Dmx%2Bc%5C%5D)
This line is perpendicular to the line ![\[y=\frac{3}{5}x+10\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B3%7D%7B5%7Dx%2B10%5C%5D)
![\[=>m*\frac{3}{5}=-1\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%2A%5Cfrac%7B3%7D%7B5%7D%3D-1%5C%5D)
![\[=>m=\frac{-5}{3}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Em%3D%5Cfrac%7B-5%7D%7B3%7D%5C%5D)
So the equation of the required line becomes ![\[y=\frac{-5}{3}x+c\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2Bc%5C%5D)
This line passes through the point (15.-5)
![\[-5=\frac{-5}{3}*15+c\]](https://tex.z-dn.net/?f=%5C%5B-5%3D%5Cfrac%7B-5%7D%7B3%7D%2A15%2Bc%5C%5D)
![\[=>c=20\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Ec%3D20%5C%5D)
So the equation of the required line is ![\[y=\frac{-5}{3}x+20\]](https://tex.z-dn.net/?f=%5C%5By%3D%5Cfrac%7B-5%7D%7B3%7Dx%2B20%5C%5D)
Among the given options, option 4 is the correct one.
The new coordinates of A'B'C' creates a triangle that is larger than ABC.
<h3>Transformation</h3>
Transformation is the movement of a point from its initial location to a new location. Types of transformation are <em>translation, reflection, rotation and dilation.</em>
If a point A(x, y) is dilated by a scale factor k, the new point is at A'(kx, ky).
Given that:
- Triangle ABC has the following coordinates: A(4 , 5), B(5 , 3), and C(2 , 3)
If it is dilated by a scale factor of 3, the new point is at:
- A'(12, 15), B'(15, 9) and C'(6, 9)
Therefore the new coordinates of A'B'C' creates a triangle that is larger than ABC.
Find out more on dilation at: brainly.com/question/10253650
9514 1404 393
Answer:
15
Step-by-step explanation:
In vector form, the equation of point p on the line can be written as ...
p = (-3, -4) +t(25 -(-3), 38 -(-4)) . . . . . for some scalar t
p = (-3, -4) +t(28, 42)
p = (-3, -4) +14t(2, 3)
where t takes on any value between 0 and 1.
If we let t = n/14 for some integer 0 ≤ n ≤ 14, then the coordinates of point p will be integers.
There are 15 values that n can have in the allowed range.
The caterpillar touches 15 points with integer coordinates.
The problem 10bf + 25bg – 21p – 14pq cannot be factored because it cannot be simplifed further. This is because there are no common factors between in any of the terms.
