We know that
The sum of the lengths of any two sides of a triangle is greater than the length of the third side (Triangle Inequality Theorem)
Let
A------> Lincoln, NE
B------> Boulder, CO
C------> third city
we know that
in the triangle ABC
AB=500 miles
BC=200 miles
AC=x
Applying the Triangle Inequality Theorem
1) 500+200 > x------> 700 > x------> x < 700 miles
2) 200+x > 500----> x > 500-200------> x > 300 miles
the solution for x is
300 < x < 700
the interval is------> (300,700)
the possible distances, d, in miles, between Lincoln, NE, and the third city, are in the range between 300 and 700 miles
open () to make 9f-6>5f-3
minus 5f to make 4f-6>-3
add 6 to make 4f>3 so f >3/4
Answer:
1085
Step-by-step explanation:
100 - 69 =31%
3500 /100 =35
35 x 31 = 1085
Answer:
w2+x6
Step-by-step explanation:
w+w+x+x+x+x+x+x will equal to w2+x6
