Question

Plz help me answer this i dont need an explanation

Answer 1

Answer:

$A(\frac{\sqrt{3} }{2} ,\frac{1}{3})\\ \\and\\\\B( 1, 1)$

Point A {√3 /2 ,1 /3}

Point B { 1, 1}

could not be the points on the unit circle.

Step-by-step explanation:

Unit circle :

A circle having a radius of one unit is called the unit circle.

Standard equation of circle given by

x² + y² = r²

r = radius of

∴ x² + y² = 1²

∴ x² + y² = 1

∴ $A(\frac{\sqrt{3} }{2} ,\frac{1}{3})\\ \\and\\\\B( 1, 1)$

Points are not on the unit circle as on substituting this x and y values

in the above equation we get

Left hand side ≠ Right-hand side

∴ $A(\frac{\sqrt{3} }{2} ,\frac{1}{3})\\ \\and\\\\B( 1, 1)$

could not be the points on the unit circle.