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borishaifa [10]
3 years ago
7

Your cousin, who is planning her wedding, is working on the seating chart for the reception. She is trying to decide which 6 peo

ple should be seated at the table closest to the head table. She has narrowed her decision down to a list of 10 friends.
If the order doesn't matter, in how many ways can she choose 6 friends from the list of 10 to sit at the table closest to the head table?
Mathematics
1 answer:
zimovet [89]3 years ago
8 0
Final list of friends = 10
Possible number of friends who can sit close to the head table = 6

This is a question of the number of combinations in choosing 6 friends from the list of 10 friends.

That is,
Number of ways = 10C6 = (10!)/[6!*(10-6)!] = 3628800/(720*24) = 210 ways.
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