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Luda [366]
4 years ago
13

Help!!!!Somebody help me solve these questions please ​

Mathematics
2 answers:
Ugo [173]4 years ago
8 0

Answer:

1. 40cm²

2.60cm²

Step-by-step explanation:

1. Area of triangle :- 1/2 * base* hight

=> 1/2*6*4=12cm²

Area of Square = 4*4 = 16cm²

Total area=( 12+16+12 )cm² =40cm²

•°• Area of trapezium = 40cm².

2. Area of rectangle = length * breadth

=>10*6= 60cm².

<h3>make me brainlist :)</h3>

kykrilka [37]4 years ago
5 0

Step-by-step explanation:

Area of a trapezium = SOPS/2 × ph

Sops is the sum of 4+10 = <u>1</u><u>4</u>

14/2 is 7. 7×4 = <u>2</u><u>8</u>

<u>A</u><u> </u><u>=</u><u> </u><u>2</u><u>8</u><u>c</u><u>m</u><u>²</u>

Area = L×W

10×6= 60cm²

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Pinto
aleksley [76]

Answer:

उत्तर:

गोलाको आयतन :4851 cm³

⁴/3 πr³=4851

r³=4851×3×7/(22*4)

r³=1157.625

r=\sqrt[3]{1157.625}

r=10.5

अब

गोलाको व्यास=2×r=10.5*2=21cm.

5 0
3 years ago
Use the Divergence Theorem to evaluate S F · dS, where F(x, y, z) = z2xi + y3 3 + sin z j + (x2z + y2)k and S is the top half of
kifflom [539]

Looks like we have

\vec F(x,y,z)=z^2x\,\vec\imath+\left(\dfrac{y^3}3+\sin z\right)\,\vec\jmath+(x^2z+y^2)\,\vec k

which has divergence

\nabla\cdot\vec F(x,y,z)=\dfrac{\partial(z^2x)}{\partial x}+\dfrac{\partial\left(\frac{y^3}3+\sin z\right)}{\partial y}+\dfrac{\partial(x^2z+y^2)}{\partial z}=z^2+y^2+x^2

By the divergence theorem, the integral of \vec F across S is equal to the integral of \nabla\cdot\vec F over R, where R is the region enclosed by S. Of course, S is not a closed surface, but we can make it so by closing off the hemisphere S by attaching it to the disk x^2+y^2\le1 (call it D) so that R has boundary S\cup D.

Then by the divergence theorem,

\displaystyle\iint_{S\cup D}\vec F\cdot\mathrm d\vec S=\iiint_R(x^2+y^2+z^2)\,\mathrm dV

Compute the integral in spherical coordinates, setting

\begin{cases}x=\rho\cos\theta\sin\varphi\\y=\rho\sin\theta\sin\varphi\\z=\rho\cos\varphi\end{cases}\implies\mathrm dV=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi

so that the integral is

\displaystyle\iiint_R(x^2+y^2+z^2)\,\mathrm dV=\int_0^{\pi/2}\int_0^{2\pi}\int_0^1\rho^4\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=\frac{2\pi}5

The integral of \vec F across S\cup D is equal to the integral of \vec F across S plus the integral across D (without outward orientation, so that

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\frac{2\pi}5-\iint_D\vec F\cdot\mathrm d\vec S

Parameterize D by

\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath

with 0\le u\le1 and 0\le v\le2\pi. Take the normal vector to D to be

\dfrac{\partial\vec s}{\partial v}\times\dfrac{\partial\vec s}{\partial u}=-u\,\vec k

Then we have

\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^1\left(\frac{u^3}3\sin^3v\,\vec\jmath+u^2\sin^2v\,\vec k\right)\times(-u\,\vec k)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{2\pi}\int_0^1u^3\sin^2v\,\mathrm du\,\mathrm dv=-\frac\pi4

Finally,

\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\frac{2\pi}5-\left(-\frac\pi4\right)=\boxed{\frac{13\pi}{20}}

6 0
4 years ago
Find the missing side length, and enter your answer in the box below. If
Zigmanuir [339]

Answer:

2.5

Step-by-step explanation:

If you know two other sides of the right triangle, it's the easiest option; all you need to do is apply the Pythagorean theorem:

a² + b² = c²

if leg a is the missing side, then transform the equation to the form when a is on one side, and take a square root:

a = √(c² - b²)

if leg b is unknown, then

b = √(c² - a²)

for hypotenuse c missing, the formula is

c = √(a² + b²)

4 0
3 years ago
3(x – 4) + 7 = 5x? Help please.
dexar [7]

Answer:

x=-2.5

Step-by-step explanation:

3x-12+7=5x

-5=2x

-2.5=x

3 0
3 years ago
Read 2 more answers
Plz help me on number 4
jekas [21]

9514 1404 393

Answer:

  6 : 5

Step-by-step explanation:

The diagram shows you that the boxes have a length (L) to width (W) ratio such that ...

  3L = <em>l</em> = 4W

  L/W = 4/3

Suppose we call the width of the box 3 units, then its length is 4 units, and we have the crate dimensions ...

  <em>l</em> = 4(3) = 3(4) = 12

  <em>w</em> = 3+3+4 = 10

Then the ratio <em>l </em>: <em>w</em> is 12 : 10 = 6 : 5.

8 0
3 years ago
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