Answer:
P(-1, 0); Q(0, -1); R(2, -1).
Step-by-step explanation:
When you reflect coordinates over the y-axis, the y-coordinates do not change, while the signs of the x-coordinates are flipped. You can see the example attached!
And so, after reflecting P'(1, 0), you would get P(-1, 0) because the sign of the x-value is flipped and the y-value does not change.
Q'(0, -1) becomes Q(0, -1) because 0 is neither negative nor positive, and the y-value does not change.
R'(-2, -1) becomes R(2, -1) because the sign of the x-value is flipped to positive and the y-value does not change.
Hope this helps!
1. your leading coefficient has to be 1 (nothing before the x^2). If there is you have to divide that out before you start.
2. Move your constant (the number without any x attached) to the other side of the equation
3. take 1/2 of the b term (the one with the x attached) and then square it and then add it to both sides
4. Factor the left side
5. Set each factor equal to 0 and solve
Here is an example:
4x^2-24x+20=0
The first term is not a 1 so we have to divide it out by 4 first
x^2-6x+5=0
Move the 5 to the other side. It becomes negative.
x^2-6x=-5
Take 1/2 of 6 (3) then square it (9) and add it to both sides.
x^2-6x+9=-5+9
Factor the left side
(x-3)(x-3)=4
(x-3)^2=4
To solve you need to square root both sides
x-3=+/-
x-3=+/-2
x=3+2=5
x=3-2=1
Those would be your two answers.
<span>Hope that helps</span>
Answer:
No, they are not.
Step-by-step explanation: can I get brainlest?
