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3 years ago

What is the smallest number greater than 100 that is :

2 answers:

8 0

I'd start by listing out the multiplies of all three past 100, like this:
102, 104, 106, 108, 110, 112, 114, 116, 118, 120, 122, 124, 126, 128, 130
104, 108, 112, 116, 120, 124, 128, 132, 136
110, 120, 130, 140
Now it's just a matter of finding the number that is the same for all three of them, which is 120.

lyudmila [28]3 years ago

6 0

The smallest number greater than 100 is divisible by ten

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Tony's taking cookies to a bake sale. He already made 70 cookies on Monday, and wants to make more on Tuesday. His pan allows hi

Alex_Xolod [135]

Y=70 +14 (7)
y= 70 + 98
y = 168

:)

8 0

3 years ago

Plz, answer the question in the photo.

AVprozaik [17]

Answer:

2 1/4

Step-by-step explanation:

hope this helps

6 0

3 years ago

If you apply the changes below to the absolute value parent function, f(x) = |Xl,

TiliK225 [7]

Answer:

• Shift 5 units to the left >>> f(x) = |x+5|

• Shift 4 units down >>> f(x) = |x| - 4

Step-by-step explanation:

If we have the parent function:

f(x) = |x|

<u>For horizontal translations:</u>

|x-a| means horizontally translated a units right
|x+a| means horizontally translated a units left

<u>For Vertical translation:</u>

|x| + b means vertically translated b units up
|x| - b means vertically translated b units down

From the translation rules, we can say:

Shift 5 units left would be:

|x+5|

and

Shift 4 units down would be:

|x| - 4

7 0

3 years ago

What is the range of the number of points scored?

MatroZZZ [7]

Answer:

I think it is A, I might be wrong.

Step-by-step explanation:

3 0

3 years ago

On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar is known to be normally dist

Fofino [41]

Answer:

a) $8469-1.645\frac{100}{\sqrt{64}}=8448.4$

$8469+1.645\frac{100}{\sqrt{64}}=8489.6$

So on this case the 90% confidence interval would be given by (8448.4;8489.6)

b) $8469-2.054\frac{100}{\sqrt{64}}=8443.33$

$8469+2.054\frac{100}{\sqrt{64}}=8494.68$

So on this case the 96% confidence interval would be given by (8443.33;8494.68)

Step-by-step explanation:

Assuming this complete problem: On the basis of extensive tests, the yield point of a particular type of mild steel-reinforcing bar is known to be normally distributed with s = 100. The composition of the bar has been slightly modified, but the modification is not believed to have affected either the normality or the value of s.

(a) Assuming this to be the case, if a sample of 64 modified bars resulted in a sample average yield point of 8469 lb, compute a 90% CI for the true average yield point of the modified bar. (Round your answers to one decimal place.)

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=8469$ represent the sample mean

$\mu$ population mean (variable of interest)

$\sigma=100$ represent the population standard deviation

n=64 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that $z_{\alpha/2}=1.645$

Now we have everything in order to replace into formula (1):

$8469-1.645\frac{100}{\sqrt{64}}=8448.4$

$8469+1.645\frac{100}{\sqrt{64}}=8489.6$

So on this case the 90% confidence interval would be given by (8448.4;8489.6)

(b) How would you modify the interval in part (a) to obtain a confidence level of 96%? (Round your answer to two decimal places.)

Since the Confidence is 0.96 or 96%, the value of $\alpha=0.04$ and $\alpha/2 =0.02$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.02,0,1)".And we see that $z_{\alpha/2}=2.054$

Now we have everything in order to replace into formula (1):

$8469-2.054\frac{100}{\sqrt{64}}=8443.33$

$8469+2.054\frac{100}{\sqrt{64}}=8494.68$

So on this case the 96% confidence interval would be given by (8443.33;8494.68)

7 0

3 years ago