You need to ask the question not a bit of dialogue xx
I assume you're asked to solve
4 cos²(<em>x</em>) - 7 cos(<em>x</em>) + 3 = 0
Factor the left side:
(4 cos(<em>x</em>) - 3) (cos(<em>x</em>) - 1) = 0
Then either
4 cos(<em>x</em>) - 3 = 0 <u>or</u> cos(<em>x</em>) - 1 = 0
cos(<em>x</em>) = 3/4 <u>or</u> cos(<em>x</em>) = 1
From the first case, we get
<em>x</em> = cos⁻¹(3/4) + 2<em>nπ</em> <u>or</u> <em>x</em> = -cos⁻¹(3/4) + 2<em>nπ</em>
and from the second,
<em>x</em> = <em>nπ</em>
where <em>n</em> is any integer.
Answer:
4 - 2x = 36
Ste4p-by-step explanation:
We have to add the ones with the same variables.
-17 + 21 = 4
-5x + 3x = -2x
4 - 2x = 36
Answer: . 2 + 3b
Step-by-step explanation: Twice b is 2b. Sum of 2 and b is 2 + b. Add them all together and combine like terms. You get your answer.
