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4 years ago

The graph of a degenerate circle is a____.

Mathematics

2 answers:

nikklg [1K]4 years ago

6 0

There are two kinds of degeneracy that occur in circles.

1. Consider the equation of circle

x² + y² - 2 x - 2 y +2=0

(x-1)² + (y-1)²=0

The circle having Zero radius is case of degeneracy. The graph of the circle having Zero radius is a point.

2. Consider another circle

x² + y² - 2 x + 2 y +8 =0

(x-1)² + (y +1)²-1-1+ 8=0

(x -1)² + (y +1)²= -6= [i√6]²

This is a circle having negative radius.As we can't predict the radius of circle , so Circle having infinite radius will have the graph of straight line. .

faust18 [17]4 years ago

3 0

<span>The graph of a degenerate circle is a point

Which mean :
A point is a degenerate circle (circle equation with zero radius)
for example: ⇒⇒ (x - 2)² + (y - 3)² = 0
</span>

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Angle measurement, help

IrinaVladis [17]

Answer:

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Step-by-step explanation:

1.) if supplement then its equal to 90, so subtract from 90

2.) 90-72= 18, so the asnwer is 18

39+2x+1=90

40+2x=90

2x=50

x=25

3.) x-24+29=296

x+5=296

x=291

4.)vertical angles so congruent, 107

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8 0

3 years ago

\begin{aligned} & 2x+7y = 3 \\\\ & x=-4y \end{aligned}

zheka24 [161]

Answer:

x = 12 , y = -3

Step-by-step explanation:

Solve the following system:

{2 x + 7 y = 3 | (equation 1)

x = -4 y | (equation 2)

Express the system in standard form:

{2 x + 7 y = 3 | (equation 1)

x + 4 y = 0 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{2 x + 7 y = 3 | (equation 1)

0 x+y/2 = -3/2 | (equation 2)

Multiply equation 2 by 2:

{2 x + 7 y = 3 | (equation 1)

0 x+y = -3 | (equation 2)

Subtract 7 × (equation 2) from equation 1:

{2 x+0 y = 24 | (equation 1)

0 x+y = -3 | (equation 2)

Divide equation 1 by 2:

{x+0 y = 12 | (equation 1)

0 x+y = -3 | (equation 2)

Collect results:

Answer: {x = 12 , y = -3

4 0

3 years ago

Provide a counterexample to the following statement: division of whole numbers is commutative

Yuri [45]

Answer:

Division is not commutative because 25÷5 does not equal 5÷25

Step-by-step explanation:

5 0

3 years ago

Given sin(−θ)=−1/6 and tanθ=−√35/35 What is the value of cosθ?

murzikaleks [220]

Answer:

$cos(\theta)=-\frac{\sqrt{35} }{6}$

Step-by-step explanation:

Recall the negative angle identity for the sine function:

$sin(- \theta)=-sin(\theta)$

Then, we can find the value of $sin(\theta)$ :

$sin(\theta)=-sin(-\theta)\\sin(\theta) =-(-\frac{1}{6} )\\sin(\theta)= \frac{1}{6}$

Now recall the definition of the tangent function:

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

Therefore, now that we know the value of $sin(\theta)$ , we can solve in this equation for $cos(\theta)$

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}\\-\frac{\sqrt{35} }{35} =\frac{1/6}{cos(\theta)} \\cos(\theta)=-\frac{\frac{1}{6} }{\frac{\sqrt{35} }{35} } \\cos(\theta)=-\frac{35}{6\,\sqrt{35} } \\cos(\theta)=-\frac{\sqrt{35} }{6}$

5 0

3 years ago

Let A = {1,2,3,..., 8, 9, 10} B = {4, 7, 10}

Dovator [93]

The answers to the questions are

(i) B - A = Ф / null set

(ii) A - B = {1, 2, 3, 5, 6, 8, 9}

(iii) (A - B) ∩ (B - A) = Ф / null set

(iv) (A - B) ∪ (B - A) = {1, 2, 3, 5, 6, 8, 9}

A set contains different elements which are mathematical objects of any kind such as numbers, points, spaces, lines e.t.c.

Different types of set are -singleton setsfinite and infinite setsempty or null sets equal sets unequal sets equivalent sets overlapping sets disjoint sets subsets super sets power sets universal sets

According to question,

i ] B - A = 0/null set

ii ] A - B = [ 1,2,3,5,6,8,9 ]

iii ] (A-B) n (B-A) = 0/ null set

iv ] (A-B) u ( B-A) = [ 1,2,3,5,6,8,9 ]

Hence, the answers to the questions are

(i) B - A = Ф / null set

(ii) A - B = {1, 2, 3, 5, 6, 8, 9}

(iii) (A - B) ∩ (B - A) = Ф / null set

(iv) (A - B) ∪ (B - A) = {1, 2, 3, 5, 6, 8, 9}

To understand more about Set Theory refer - brainly.com/question/13458417#SPJ9

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2 years ago