Answer:
-6
Step-by-step explanation:
hope this was helpful.
Eq1) 2r+2s=50
eq2) 2r-s=17
solve for s in equation2 (eq2)
-s=17-2r
s=-17+2r
Substitute s into equation1 (eq1)
2r+2(-17+2r)=50
2r-34+4r=50
6r-34=50
6r=50+34
6r=84
r=14
Substitute into either equation and solve for s
2(14)-s=17
28-s=17
-s=17-28
-s=-11
s=11
There would be 17 short answer questions on the test.
Let's say that BC is x, so that AB is 4x, and AE = y.
The shaded area then is represented by 4xy/2 = 2xy.
The total area is represented by (4x+x)*y = 5xy.
The fraction of these is 2xy/5xy = 2/5.
Chocolatey107 is right!
