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Maru [420]
3 years ago
5

PLEASE HELP URGENTttttttt

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0
Y=2/3x - 1 
written in slope intercept form

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144 students enter a spelling bee,but only 1/6 of the group will make into the semi-final round, and only 2/3 that group will ma
Alexus [3.1K]

Answer:

96

Step-by-step explanation:

144 x 2 = 288

288/3 = 96

3 0
3 years ago
Find the domain and range of the relation given to the right.
loris [4]

Answer:

Step-by-step explanation:

D:(0,10)

R:(14, infinitly)

6 0
3 years ago
A city manager made a scatter plot of the number or retail store in a certain city over the years. the scatter plot had a trend
Fiesta28 [93]

Answer:

155

Step-by-step explanation:

The problem sounds complicated, but it's not. Let's analyse.

The city manager have come up with an equartion y=11x +12, with Y is the total number of the stores and X stands for how long it has been since 2003.

We can't explain how the manager came up with this equation, so iwe don't need to think of if the equation is real or not. Let's just base on what we have.

Because the equation aboce is a trendy line, it means that it would likely to be true with any X ( number of years since 1990).

In Tracy's case, the year is 2003, so it has been 2003 - 1990 = 13 years since 1990. This is the X in the equation. Now we only need to find Y in the equation, which is the number of retail stores there were in 2003, exactly what the problem asks.

y= 11x + 12

=> In Tracy's case: y= 11*13 + 12= 155

So the number of retail stores there were in 2003 was 155

5 0
2 years ago
[Geometry Basics] I'm just checking if this is correct:
Leno4ka [110]
\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~ -9 &,& -1~)
\end{array}\qquad
%   coordinates of midpoint 
\left(\cfrac{ x_2 +  x_1}{2}\quad ,\quad \cfrac{ y_2 +  y_1}{2} \right)
\\\\\\
\left( \cfrac{-9+x}{2}~~,~~\cfrac{-1+y}{2} \right)=\stackrel{midpoint}{(8,14)}\implies 
\begin{cases}
\cfrac{-9+x}{2}=8\\\\
-9+x=16\\
\boxed{x=25}\\
-------\\
\cfrac{-1+y}{2} =14\\\\
-1+y=28\\
\boxed{y=29}
\end{cases}

\bf -------------------------------\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ x &,& y~) 
%  (c,d)
&&(~10 &,& 12~)
\end{array}\qquad
\\\\\\
\left( \cfrac{10+x}{2}~~,~~\cfrac{12+y}{2} \right)=\stackrel{midpoint}{(6,9)}\implies 
\begin{cases}
\cfrac{10+x}{2}=6\\\\
10+x=12\\
\boxed{x=2}\\
-------\\
\cfrac{12+y}{2} =9\\\\
12+y=18\\
\boxed{y=6}
\end{cases}
3 0
3 years ago
Which of the following is equvalent to (16^3/2)^1/2<br>A. 6<br>B. 8<br>C. 12<br>D. 64
bagirrra123 [75]
B. 8 is the answer.

Simplify to 2^4^(3/4) then 2^3 then that simplies to 8
6 0
3 years ago
Read 2 more answers
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