Answer:
A. 
B. Perimeter = 190.6 yd
Step-by-step explanation:
A. Distance between P(10, 50) and R(80, 10):





(nearest tenth)
B. Distance around the park = Perimeter = PR + PQ + QR
PR = 80.6 yd
PQ = |50 - 10| = 40 yd
QR = |80 - 10| = 70 yd
Perimeter = 80.6 + 40 + 70
Perimeter = 190.6 yd
Step-by-step explanation:
Given
f(x) = 2x - 1
f^-1 (x) = ?
Now
Let y = f(x)
or y = 2x - 1
Interchanging the role of x and y
x = 2y - 1
x + 1 = 2y
y = <u>x </u><u>+</u><u> </u><u>1</u>
2
Therefore f^-1(x) = <u>x </u><u>+</u><u> </u><u>1</u>
2
Hope it will help you :)
Since the pool is square, the four sides are equal.
Therefore the length of one side = sqrt(292) = 17.1 to the nearest tenth.