Question

PLz help me!

Answer 1

Start by finding the slope using the slope "formula" $\frac{y_2-y_1}{x_2-x_1}$:

$x_2=2 \newline y_2=10 \newline \newline x_1=-3 \newline y_1=5 \newline \newline \frac{10-5}{2-(-3)}=1$

Now, write y=mx+b, substituting the value you found above (the slope) for m:

$y=(1)x+b \text{ or } y=x+b$

Now, substitute one of the given points for x and y to solve for b. Let's use (2,10):

$y=x+b \newline 10=2+b \newline b=8$

Now, put it all together:

$y=x+8$

That's the equation of the line!

Answer 2

Slope = (10 - 5) / (2 + 3) =  1

Therefore, y = x + b

At point (2, 10)

10 = 2 + b
b = 8

Therefore : y = x + 8

Answer:  y = x + 8 (Answer A)