Question

What is the value of n such that the expression x² + 11x + n is a perfect square trinomial? a. 11. b. 25. c. 30. d.25. e.36

Answer 1

Answer:

The value of n is 30.25.

Step-by-step explanation:

The given expression is

$x^2+11x+n$             ....(1)

The perfect square trinomial are defined as

$(x+y)^2=x^2+2xy+y^2$                 .....(2)

On comparing (1) and (2), we get

$2y=11$

$y=\frac{11}{2}$

The given expression is perfect square trinomial if

$n=y^2$

$n=(\frac{11}{2})^2$

$n=\frac{121}{4}$

$n=30.25$

Therefore the value of n is 30.25.

Answer 2

The value of n such that the expression x² + 11x + n is a perfect square trinomial can be determined by taking the formula: 11 = 2b where b is a real number. b is equal to 11/2. The third term is equal to (11/2)^2 equal to 121/4 equal to 30.25.