Answer:
(f + g)(x) = x^2 + 3x - 6
Step-by-step explanation:
Given f(x) = x^2 + x − 2 and g(x) = 2x − 4
Plug in:
(f + g)(x) = x^2 + x − 2 + 2x − 4
(f + g)(x) = x^2 + 3x - 6
The answer is
A. No, because 1 x-value corresponds to 2 different y-values
Answer:
no
Step-by-step explanation:
4x +12 = 4
4(2) +12 =/= 4
8 +12 =/= 4
8 +12 = 20
(sorry if it doesn't make sense,I tried)