All categories

3 years ago

Evaluate 15+102 times parentheses 12 minus parentheses 12-3×2 parentheses parentheses +6

Mathematics

1 answer:

larisa [96]3 years ago

8 0

Answer:(15 + 102)(12) - (12-3•2)

Step-by-step explanation:

Well first you would add 15+102 = 117

Then times 117(12) = 1,404

Later you are gonna subtract this number but first let's solve

12-3•2

12-3 = 9

9(2) = 18

Finally you are gonna subtract

1,404 - 18

Which = 1,386

So 1,386 is your answer

You might be interested in

In the circle, O is the centre and AB is a diameter.

Burka [1]

Answer:

Step-by-step explanation:

Answer:

a). m∠a = 62°

b). m∠b = 118°

Step-by-step explanation:

a). Since, an angle inscribed in a semicircle is a right angle,

m∠ACB = 90°

By triangle sum theorem in ΔABC,

m∠CAB + m∠ACB + m∠ABC = 180°

28° + 90° + m∠ABC = 180°

118° + m∠ABC = 180°

m∠ABC = 180°- 118°

a = 62°

b). Since, quadrilateral ABCD is a cyclic quadrilateral,

m∠ADC + m∠ABC = 180°

b + a = 180°

b + 62° = 180°

b = 180° - 62°

b = 118°

7 0

3 years ago

Find the constant difference for a hyperbola with foci (-3.5, 0) and (3.5, 0) and a point on the hyperbola (3. 5, 24).

Solnce55 [7]

Answer:

2a=1

Step-by-step explanation:

The constant difference for a hyperbola $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$ is $2a.$

1. Since hyperbola has foci (-3.5, 0) and (3.5, 0), then $c=3.5.$ Note that $c=\sqrt{a^2+b^2},$ then

$\sqrt{a^2+b^2}=3.5\Rightarrow a^2+b^2=3.5^2.$

2. Since point (3.5,24) lies on the hyperbola, then

$\dfrac{3.5^2}{a^2}-\dfrac{24^2}{b^2}=1.$

3. Solve the system of two equations:

$\left\{\begin{array}{l}a^2+b^2=3.5^2\\\dfrac{3.5^2}{a^2}-\dfrac{24^2}{b^2}=1\end{array}\right.$

From the 1st equation,

$b^2=3.5^2-a^2,$

then

$\dfrac{3.5^2}{a^2}-\dfrac{24^2}{3.5^2-a^2}=1,\\ \\\dfrac{3.5^2(3.5^2-a^2)-24^2a^2}{a^2(3.5^2-a^2)}=1,\\ \\3.5^4-3.5^2a^2-24^2a^2=3.5^2a^2-a^4,\\ \\a^4-a^2(2\cdot 3.5^2+24^2)+3.5^4=0,\\ \\a^4-600.5a^2+150.0625=0,\\ \\D=(-600.5)^2-4\cdot 150.0625=360000,\\ \\a^2_{1,2}=\dfrac{600.5\pm 600}{2}=\dfrac{1}{4},600\dfrac{1}{4}.$

For $a^2=\dfrac{1}{4},\ b^2=3.5^2-0.25=12.$

For $a^2=600\dfrac{1}{4},\ b^2=3.5^2-600.25$ this is impossible, then $a^2=600\dfrac{1}{4}$ is extra solution.

Hence, $a=\dfrac{1}{2}$ and $2a=1.$

5 0

3 years ago

7 a) The table shows the masses of the planets in our solar system.

babunello [35]

Answer:

1. Neptune (lightest)
2. Jupiter
3. Mercury
4. Venus
5. Saturn
6. Earth
7. Mars
8. Uranus (heaviest)

Explanation:

Neptune: 1.02 x 1026 = 1046.52 kg
Jupiter: 1.90 x 1027 = 1951 . 3 kg
Mercury: 3.30 x 1023 = 3375.9 kg
Venus: 4.87 x 1024 = 4986.88 kg
Saturn: 5.68 x 1026 = 5827.68 kg
Earth: 5.97 x 1024 = 6113.28 kg
Mars: 6.42 x 1023 =6567.66 kg
Uranus: 8.68 x 1025 = 8897 kg

hope this was what you were looking for :)

5 0

2 years ago

Marcia has a sunflower garden. The plants are currently 36 inches tall and are growing at a rate of 4 inches each week. Write an

alexgriva [62]

H = 4w + 36
is your equation

6 0

4 years ago

Question 18: Please help, I'm not sure but I think the answer is either C or D.

Ad libitum [116K]

Answer:I think it is C

Step-by-step explanation:

3 0

3 years ago