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Anettt [7]
4 years ago
7

What is the domain of the following function?

Mathematics
1 answer:
Goryan [66]4 years ago
7 0

Answer:

All real numbers

Step-by-step explanation:

The domain of this is all real numbers.  The x values will never keep going down (to negative infinity) and will also never stop growing (to positive infinity).

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Let f(x) = 5x ^ 2 - x + 1 and g(x) = - 3x . Evaluate the composition (fg)(1)
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F(x) = 5(-3x) ^2 - (-3x) + 1
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The answer to this question of yours is B
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If y = 8 when x<br> 8 when x = 3, find y when x = 45.
Zarrin [17]

Answer:

y = 120

Step-by-step explanation:

y = kx ur finding k

8 = k 3 get k alone by dividing both sides by 3 --> 8/3 = k

k = 8/3

Y = 8/3 45 now your finding Y when x is 45

Y = 120

to make sure do 120 = 8/3 45 should equal the same

4 0
3 years ago
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Alex17521 [72]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Write a polynomial of degree 5 with zero x=0,i square root 7, -2i
professor190 [17]

Answer:

P(x)=x^5+11x^3+28x

Step-by-step explanation:

<u>Roots of a polynomial</u>

If we know the roots of a polynomial, say x1,x2,x3,...,xn, we can construct the polynomial using the formula

P(x)=a(x-x_1)(x-x_2)(x-x_3)...(x-x_n)

Where a is an arbitrary constant.

We know three of the roots of the degree-5 polynomial are:

x_1=0;\ x_2=\sqrt{7}\boldsymbol{i}:\ x_3=-2\boldsymbol{i}

We can complete the two remaining roots by knowing the complex roots in a polynomial with real coefficients, always come paired with their conjugates. This means that the fourth and fifth roots are:

x_4=-\sqrt{7}\boldsymbol{i}:\ x_3=+2\boldsymbol{i}

Let's build up the polynomial, assuming a=1:

P(x)=(x-0)(x-\sqrt{7}\boldsymbol{i})(x+\sqrt{7}\boldsymbol{i})(x-2\boldsymbol{i})(x+2\boldsymbol{i})

Since:

(a+b\boldsymbol{i})\cdot (a-b\boldsymbol{i})=a^2+b^2

P(x)=(x)(x^2+7)(x^2+4)

Operating the last two factors:

P(x)=(x)(x^4+11x^2+28)

Operating, we have the required polynomial:

\boxed{P(x)=x^5+11x^3+28x}

7 0
3 years ago
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