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Volgvan
3 years ago
9

On a coordinate plane, 3 points are plotted. The points are (1, 80), (2, 20), (3, 5). Which function can be used to represent th

e graphed geometric sequence? f(x) = 80(One-fourth) Superscript x minus 1 f(x) = 320(One-fourth) Superscript x minus 1 f(x) = 80(4)x – 1 f(x) = 320(4)x – 1
Mathematics
1 answer:
kakasveta [241]3 years ago
3 0

Answer:

(A)f(x)=80\left(\dfrac{1}{4}\right)^{x-1}

Step-by-step explanation:

Given the three points plotted on a coordinate plane

  • (1, 80)
  • (2, 20)
  • (3, 5)

Let us consider the values in the y-axis i.e. f(x)

80, 20, 5

We notice that each succeeding term occurs by the division of the previous term by 4.

Precisely:

\dfrac{80}{4} =20\\\dfrac{20}{4} =5

This is a geometric sequence where the:

First Term =80

Common ratio =\dfrac{1}{4}

Therefore, the function which can be used to graph the geometric sequence is:

f(x)=80\left(\dfrac{1}{4}\right)^{x-1}

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