Question

Using the quadratic formula to solve 7x2 – x = 7, what are the values of x? StartFraction 1 plus-or-minus StartRoot 195 EndRoot i Over 14 EndFraction StartFraction 1 plus-or-minus StartRoot 197 EndRoot Over 14 EndFraction StartFraction 1 plus-or-minus StartRoot 195 EndRoot Over 14 EndFraction StartFraction 1 plus-or-minus StartRoot 197 EndRoot i Over 14 EndFraction

Answer 1

Answer:

B

Step-by-step explanation:

Answer 2

Answer:

$x=\frac{1(+/-)\sqrt{197}} {14}$

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$7x^{2} -x=7$  

equate to zero

$7x^{2} -x-7=0$  

so

$a=7\\b=-1\\c=-7$

substitute in the formula

$x=\frac{-(-1)(+/-)\sqrt{-1^{2}-4(7)(-7)}} {2(7)}$

$x=\frac{1(+/-)\sqrt{197}} {14}$