Answer:
1) g = -8 (one solution)
2) b = 0 (infinitely many solutions)
3) w = 5/6 (one solution)
4) c = 0 (infinitely many solutions)
Step-by-step explanation:
1) 1/2g -4 = 2g - 1/2g + 4
1/2g -2g +1/2 g = 8
-g = 8
2) 5.3-5.3 = 2.1b + b - 3.1b
0=0
3) 3/4w+ 3/4w = 10/4 - 5/4
3/2w = 5/4
w = (5/4) / (3/2)
w = 5/6
4) 5.7c + 3.2c - 7.8c - 1.1c = 1.5 - 1.5
0 = 0
Answer:
C . 63 + 36 = 9(7 + 4)
Step-by-step explanation:
Jenna sold 63 bracelets at one craft fair and 36 bracelets at a second craft fair. Which expression correctly applies the distributive property to show equivalent expressions for the total number of bracelets she sold?
63 + 36 = (3)(21) + (9)(4)
63 + 36 = (7)(9) + (12)(3)
63 + 36 = 9(7 + 4)
63 + 36 = 3(21 + 9)
To “distribute” means to divide something or give a share or part of something.
According to the distributive property, multiplying the sum of two or more addends by a number will give the same result as multiplying each addend individually by the number and then adding the products together.
To determine the distributive property to show equivalent expression, find the common factors of 63 and 36
63 = 3, 7, 9, 21,
36 = 2, 3, 4, 6, 9, 12, 18,
Common factors of 63 and 36 are 3 and 9
Using 3
3(21 + 12)
Using 9
9(7 + 4)
3(21 + 12) is not one of the options, therefore, 9(7 + 4) is the answer
Option C gives the distributive property
63 + 36 = 9(7 + 4)
63 + 36 = 63 + 36
Answer:
700
Step-by-step explanation:
The '7' in the number 1273 ..it is in the second place which represents 'tens' so it is equal to '70' ten times this amount would be 700. If you have a list of numbers to choose from.....choose one with the '7' in the THIRD position.
Answer:
The fourth term of the expansion is -220 * x^9 * y^3
Step-by-step explanation:
Question:
Find the fourth term in (x-y)^12
Solution:
Notation: "n choose k", or combination of k objects from n objects,
C(n,k) = n! / ( k! (n-k)! )
For example, C(12,4) = 12! / (4! 8!) = 495
Using the binomial expansion formula
(a+b)^n
= C(n,0)a^n + C(n,1)a^(n-1)b + C(n,2)a^(n-2)b^2 + C(n,3)a^(n-3)b^3 + C(n,4)a^(n-4)b^4 +....+C(n,n)b^n
For (x-y)^12, n=12, k=3, a=x, b=-y, and the fourth term is
C(n,3)a^(n-3)b^3
=C(12,3) * x^(12-3) * (-y)^(3)
= 220*x^9*(-y)^3
= -220 * x^9 * y^3
