Question

Consider the equation 1/4 (2a-20x)=3+bx.

Answer 1

Answer:

a=6, b=-5

a=12, b=-5

Step-by-step explanation:

We have the equation

$\frac{1}{4}(2a-20x)=3+bx$

we will try to resolve for $x$ in terms of $a$ and $b$

Then

$\frac{1}{4}(2a-20x)=3+bx\\\frac{a}{2}-5x=3+bx\\\frac{a}{2}-3=5x+bx\\\frac{a-6}{2}=(5+b)x\\\frac{a-6}{2}\frac{1}{5+b}=x\\\frac{a-6}{10+2b}=x$

Note that if the denominator is 0, then the division is undefined and therefore there would be no solution for x.

Then, the denominator is 0 if

$10+2b=0\\b=-5$.

Then, for the pairs

a=6, b=-5 and a=12, b=-5, there is no solution for x.