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erastovalidia [21]
4 years ago
9

Consider the equation 1/4 (2a-20x)=3+bx.

Mathematics
1 answer:
Misha Larkins [42]4 years ago
7 0

Answer:

a=6, b=-5

a=12, b=-5

Step-by-step explanation:

We have the equation

\frac{1}{4}(2a-20x)=3+bx

we will try to resolve for x in terms of a and b

Then

\frac{1}{4}(2a-20x)=3+bx\\\frac{a}{2}-5x=3+bx\\\frac{a}{2}-3=5x+bx\\\frac{a-6}{2}=(5+b)x\\\frac{a-6}{2}\frac{1}{5+b}=x\\\frac{a-6}{10+2b}=x

Note that if the denominator is 0, then the division is undefined and therefore there would be no solution for x.

Then, the denominator is 0 if

10+2b=0\\b=-5.

Then, for the pairs

a=6, b=-5 and a=12, b=-5, there is no solution for x.

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