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anygoal [31]
3 years ago
6

Assume your computer clock runs at the speed of 2.5 GHz (G=10^9).

Computers and Technology
1 answer:
azamat3 years ago
7 0

Answer:

a) T=4*10^{-4}μs

b) N=2.5*10^6 cycles

c) 10000 programs.

Explanation:

a) We know that the frequency is the inverse of the period, so:

f=\frac{1}{T}\\\\T=\frac{1}{f}\\T=4*10^{-10}s

1μs is equal to 1*10^{-6}s

so T=4*10^{-4}us

b) If in a second there are 2.5*10^9 cycles:

N=2.5*10^9*(1*10^{-3})=2.5*10^6 cycles

c) we have to make a conversion, we know that a program takes 100*10^(-3) milliseconds, that is, 1*10^(-4) seconds so in 1 second we can execute:

P=\frac{1s}{1*10^{-4}s}=10000

10000 programs.

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