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3 years ago

7

Samantha has a pig enclosure that is 4 feet by 6 feet in her backyard. She wants to double the area of the enclosure by increasi

ng the length and the width by the same amount. By how many feet will the length and the width be increased? Round to the nearest hundredth if necessary.

1 answer:

luda_lava [24]3 years ago

4 0

Answer:

Step-by-step explanation:

The answer is 48 feet because 4x6=24 and 24x2=48

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Find the difference. Write your answer in standard form. ( 3x3 + x-4) - (4x² + 2x - 5) The difference is?

lukranit [14]

Answer:

Step-by-step explanation:

3x³ + x - 4 - (4x² + 2x - 5) = 3x³ + x - 4 - 4x² - 2x + 5

Now combine like terms

= 3x³ - 4x² + <u>x - 2x</u> <u>- 4 + 5</u>

= 3x³ - 4x² -x + 1

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3 years ago

Read 2 more answers

Find the uncertainty in a calculated average speed from the measurements of distance and time. Average speed depends on distance

zzz [600]

Answer:

$\frac{\Delta v}{v}=0.426$

Step-by-step explanation:

you have that the average sped is given by the following formula:

$v(x,t)=\frac{x}{t}$

The uncertainty formula for a division is given by:

$\frac{\Delta v}{v}=\sqrt{(\frac{\Delta x}{x})^2+(\frac{\Delta t}{t})^2}$ (1)

Δv: uncertainty in speed

Δx: uncertainty in the distance = 0.9m

Δt: uncertainty in time = 0.7s

x: distance = 8.1m

t: time = 1.7s

You replace the values of all parameters in the equation (1):

$\frac{\Delta v}{v}=\sqrt{(\frac{0.9}{8.1})^2+(\frac{0.7}{1.7})^2}\\\\\frac{\Delta v}{v}=0.426$

Hence, the relation between the uncertainty in the average velocity is 0.426

4 0

3 years ago

Center (8,9) and radius r=10

LekaFEV [45]

Answer:

A. Standard form: $(x-8)^2+(y-9)^2=100$

B. General form: $x^2+y^2-16x-18y+45=0$

Step-by-step explanation:

We have been given that center of a circle is at point (8,9) and radius of our circle is 10 units. We are asked to write the equation of our circle.

A. Since we know that the equation of a circle in standard form is: $(x-h)^2+(y-k)^2=r^2$ , where,

(x,y) = Any point on circle,

(h,k) = Center of the circle,

r = Radius of the circle.

Upon substituting our given values in standard form of circle's equation we will get,

$(x-8)^2+(y-9)^2=10^2$

$(x-8)^2+(y-9)^2=100$

Therefore, the equation of our given circle in standard form will be $(x-8)^2+(y-9)^2=100$ .

B. Since we know that equation of a circle in general form is: $x^2+y^2+Ax+By+C=0$ , where, A, B and C are constants.

Upon expanding our standard form of equation we will get,

$x^2-16x+64+y^2-18y+81=100$

$x^2-16x+64+y^2-18y+81-100=100-100$

$x^2-16x+y^2-18y+64+81-100=0$

$x^2-16x+y^2-18y+45=0$

$x^2+y^2-16x-18y+45=0$

Therefore, the equation of our given circle in general form will be $x^2+y^2-16x-18y+45=0$ .

7 0

3 years ago

2. b = 10 feet area = 35 feet 2 Find the height of the triangle

Andreyy89

Answer:

Height = 7

Step-by-step explanation:

35*2

70

70/10

7

3 0

3 years ago

Hich function has a range of {y|y ≤ 5}?

marshall27 [118]

Answer:

$f(x)=-(x-4)^{2}+5$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

if a>0 -----> the parabola open upward (vertex is a minimum)

if a<0 -----> the parabola open downward (vertex is a maximum)

<u>Verify each case</u>

case A) $f(x)=(x-4)^{2}+5$

The vertex is the point $(4,5)$

$a=1$

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [5,∞)

$y\geq5$

case B) $f(x)=-(x-4)^{2}+5$

The vertex is the point $(4,5)$

$a=-1$

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,5]

$y\leq 5$

case C) $f(x)=(x-5)^{2}+4$

The vertex is the point $(5,4)$

$a=1$

a>0 -----> the parabola open upward (vertex is a minimum)

The range is the interval--------> [4,∞)

$y\geq4$

case D) $f(x)=-(x-5)^{2}+4$

The vertex is the point $(5,4)$

$a=-1$

a<0 -----> the parabola open downward (vertex is a maximum)

The range is the interval--------> (-∞,4]

$y\leq 4$

4 0

3 years ago