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3 years ago

6

1. What digit is in the tenths place when 12.03 is multiplied by .74?

1 answer:

ioda3 years ago

5 0

Answer:

9

Step-by-step explanation:

12.03 x 0.74=8.9022

the first number after the decimal is the tenths place, the second is the hundreths, the third is the thousandths. Excuse my spelling Im 13.

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Six students are to be seated in a row of 6 chairs. if three of thses students must be seated together, how many ways could this

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3 years ago

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Dr. Wellbee advised his patients to drink 8 eight-ounce glasses of water every day for every 50 pounds of weight. If Kelby weigh

Sever21 [200]

A right triangle has a 30o angle. The leg adjacent to the 30o angle measures 25 inches.

What is the length of the other leg? Round to the nearest tenth.

14.4 in.21.7 in.28.9 in.<span>43.3 in.</span>

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3 years ago

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9x^2-y^2 in factored form

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Answer:

$(3a-y)(3a+y)$

Step-by-step explanation:

This is a difference of squares that has the form and factors to:

$a^2x^2-b^2 = (ax-b)(ax+b)$

Here take the square root of each term for the factors.

$9a^2-y^2 = (3a-y)(3a+y)$

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3 years ago

A manufacturer makes chocolate squares that have a target weight of 8 g. Quality control engineers sample 30 chocolate squares t

posledela

Using the <em>normal distribution and the central limit theorem</em>, it is found that the power of the test is of 0.9992 = 99.92%.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is $\mu = 8.5$ .

The standard deviation is $\sigma = 0.87$ .

A sample of 30 is taken, hence $n = 30, s = \frac{0.87}{\sqrt{30}} = 0.1588$ .

The power of the test is given by the probability of a sample mean above 8, which is <u>1 subtracted by the p-value of Z when X = 8</u>, so:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem:

$Z = \frac{X - \mu}{s}$

$Z = \frac{8 - 8.5}{0.1588}$

$Z = -3.15$

$Z = -3.15$ has a p-value of 0.0008.

1 - 0.0008 = 0.9992.

The power of the test is of 0.9992 = 99.92%.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can check brainly.com/question/24663213

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2 years ago

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Margarita [4]

16*3=48

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