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stellarik [79]
3 years ago
6

Two genes are 22 map units apart on the same chromosome. A true-breeding GGhh individual is crossed to a true-breeding ggHH indi

vidual. The F1 offspring are mated to gghh individuals. If this testcross produces 1000 offspring, how many of them would you expect to be GgHh?
Select one:
a. 390
b. 250
c. 220
d. 110
Biology
1 answer:
Oliga [24]3 years ago
4 0

Answer:

d. 110

Explanation:

<u>Parental cross</u>: Gh/Gh  x  gH/gH

<u>F1</u>: Gh/gH

<u></u>

<u>The following test cross experiment is done:</u>

Gh/gH  x  gh/gh

<u>Gametes produced by these individuals:</u>

- gh/gh: gh (probability of 1)

- Gh/gH:

  • Gh (parental)
  • gH (parental)
  • GH (recombinant)
  • gh (recombinant)

The formula that relates genetic distance with recombination frequency is:

<h3>Genetic Distance (m.u.)= Recombination Frequency X 100</h3>

In this problem:

22 m.u. / 100 = Recombination Frequency

0.22 = Recombination Frequency

The recombination frequency altogether is 0.22, but there are 2 possible types of recombinant gametes and when one is generated, the other one is generated as well. Therefore, each recombinant gamete has a frequency of half the total recombination frequency: 0.11

In an offspring of 1000 individuals, I would expect 110 to be GH/gh.

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