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3 years ago

A fair coin is tossed five times. Calculate the probability of obtaining at least one head.

Mathematics

2 answers:

stealth61 [152]3 years ago

4 0

Answer:

Step-by-step explanation:

dont know sorry

Alexus [3.1K]3 years ago

4 0

Answer:

1/5

Step-by-step explanation:

There are 5 heads so the provability of having one head is 1/5

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A painting has an area of 108 square inches. The dimensions of the painting are 12 and x + 3. What is the perimeter of the paint

dmitriy555 [2]

Answer:

42 inches square

Step-by-step explanation:

x=6

108/12=9

9-3=6

12+12+9+9=42

6 0

3 years ago

Read 2 more answers

State of the triangles in each pair are similar. If so, state how you know they are similar and complete the similarity statemen

Blababa [14]

Answer:

SSS, UVD, the answer is D

Step-by-step explanation:

90/9 = 10

70/7 = 10

80/8 = 10

triangle LMN congruent triangle UVD

6 0

3 years ago

Need help with problem 5, Thank you!<br><br><br> Sorry for the glare

MAXImum [283]

Answer:

x = 57

Step-by-step explanation:

A triangles degrees add up to 180

67 + 56 = 123

180 - 123 = 57

6 0

3 years ago

Find the area of the region bounded by the y-axis, the line y=6, and the line y = 1/2.

Ghella [55]

Solution:

As region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis.

We consider a line , one dimensional if it's thickness is negligible.

So, Line is two dimensional if it's thickness is not negligible becomes a quadrilateral.

So, Area (region bounded by y-axis, the line y=6, and the line y=1/2 is a line segment of definite length on y-axis)= Area of line segment between [,y=6 and y=1/2.]= 6-1/2=11/2 units if we consider thickness of line as negligible.

4 0

3 years ago

Solve the following absolute value equations. Show the solution set and check your answers. |0.3-3/5k|-0.4=1.2

9966 [12]

Answer:

**The equation is not clear, so I have provided both options**

<h3><u>Option 1</u></h3>

$\left|0.3-\dfrac{3}{5}k\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5}k\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5}k=1.6$

$\implies -\dfrac{3}{5}k=1.3$

$\implies k=-\dfrac{13}{6}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5}k)=1.6$

$\implies -0.3+\dfrac{3}{5}k=1.6$

$\implies \dfrac{3}{5}k=1.9$

$\implies k=\dfrac{19}{6}$

<h3><u>Option 2</u></h3>

$\left|0.3-\dfrac{3}{5k}\right|-0.4=1.2$

$\implies \left|0.3-\dfrac{3}{5k}\right|=1.6$

<u>Solution 1</u>

$\implies 0.3-\dfrac{3}{5k}=1.6$

$\implies -\dfrac{3}{5k}=1.3$

$\implies -3=6.5k$

$\implies k=-\dfrac{6}{13}$

<u>Solution 2</u>

$\implies -(0.3-\dfrac{3}{5k})=1.6$

$\implies -0.3+\dfrac{3}{5k}=1.6$

$\implies \dfrac{3}{5k}=1.9$

$\implies 3=9.5k$

$\implies k=\dfrac{6}{19}$

6 0

2 years ago