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3 years ago

A fair coin is tossed five times. Calculate the probability of obtaining at least one head.

Mathematics

2 answers:

stealth61 [152]3 years ago

4 0

Answer:

Step-by-step explanation:

dont know sorry

Alexus [3.1K]3 years ago

4 0

Answer:

1/5

Step-by-step explanation:

There are 5 heads so the provability of having one head is 1/5

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Find the surface area of a sphere with a radius of 30 m. leave your answer in terms of pi @Directrix

insens350 [35]

The formula for surface area of a sphere: A = 4 pi r^2.
Since the radius is 30 m then A = 4pi30^2.
30^2 x 4 =3600
A=3600pi m

5 0

3 years ago

Read 2 more answers

Laine reads 25 pages in 30 minutes. If she reads 200 pages at the same rate how long will it take her?

Veronika [31]

Answer:

4 hours

Step-by-step explanation:

25 pages -> 30 min

5 pages -> 6 min

200 pages -> 6*40 min =240 min

240/60= 4

Thus, the answer is 4 hours

7 0

4 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

4 years ago

There is the question since it was blurry.

Wewaii [24]

I think it would be 10,200

6 0

4 years ago

GIVING 10 POINTS ANSWER ASAP PLEASE

Irina18 [472]

Answer:

the answer is n, 225 so u can use another app to make sure u find ur answer

8 0

3 years ago