HELP PLEASE!!!!!!!!!!!!!!!!!!

Help me find the answerr

notka56 [123]

Answer:

m∠3 = 24°

Step-by-step explanation:

By the theorem,

"Intercepted arc measures the double of the inscribed angle formed by two chords meeting at one point of the circle."

In the given picture,

∠3 is the inscribed angle subtended by the arc ED and is the intercepted arc.

Therefore, m∠3 = $\frac{1}{2}m(\text{arc}ED)$

m∠3 = $\frac{1}{2}(48)$

= 24°

Measure of angle 3 is 24 degrees.

6 0

3 years ago

I would like to know the value of b and c

Ratling [72]

Answer:

a = 3, b = 8, c = 14

Step-by-step explanation:

First, we can organize this, putting lower values first.

2, 3, 3, 5, 9, 9, 11, 12

a , b , c somewhere there

Given this information, one thing we can look at first is the mode. The mode is 3, so there must be more 3s than any other number. Currently, there are 2 3s and 2 9s, so there must be at least one more 3 and no more 9s to make that true. Therefore, a, b, or c is 3. Therefore, we have

2, 3, 3, 3, 5, 9, 9, 11, 12

2 of a, b, c somewhere in there

Next, the median is 8. In our current state, the median is 5. There are 9 numbers, with 11 total including the 2 remaining values. Because there will be an odd amount of values, the median must be a number on the list. Therefore, our list is

2, 3, 3, 3, 5, 8, 9, 9, 11, 12

1 of a, b, c somewhere in there

There are 4 numbers above the median and 5 numbers below right now. To balance this out, there must be another number above the median. As a consequence, the remaining value must be greater than 8.

Finally, we know that the range is 12, so maximum - minimum = 12. Because the remaining number must be greater than 8, the minimum number is 2, no matter what. Therefore,

maximum - 2 = 12

add 2 to both sides to isolate maximum

maximum = 14

There is no 14 currently on the list, so the remaining value must be 14.

Our a, b, and c are as follows, in order from smallest to largest:

3, 8, 14

8 0

2 years ago

Please helpppppp meeeeeee

m_a_m_a [10]

The pictures won’t load for some reason

7 0

3 years ago

Which is greater: 25% of 15 or 15% of 25? Explain your reasoning using mathematical evidence or visual models.

d1i1m1o1n [39]

15% of 25 is the greatest of the two.

Answer:

25% of 15 is 3.75

15% of 25 is also 3.75

15 - 3.75 = 11.25

25 - 3.75 =21.25

Compare and then determine.

11.25 < 21.25

8 0

2 years ago

Read 2 more answers

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

3 years ago