The domain of the function is (-∞,∞) and the simplified expression is x²-6x-40 .
A function's domain and range are its constituent parts. A function's range is its potential output, whereas its domain is the set of all possible input values. Range, Domain, and Function. A is the domain and B is the co-domain if a function f: A B exists that maps every element of A to an element in B. 'b', where (a,b) R, provides the representation of an element 'a' under a relation R. The set of images is the function's range.
The given functions are
f(x)=6x+24
g(x)=x²-16
Now we have to find (g-f)(x) .
(g-f)(x)=x²-16-6x-24
or,(g-f)(x)=x²-6x-40
or,(g-f)(x)=x²-10x+4x-40
or,(g-f)(x)=x(x-10)+4(x-10)
or,(g-f)(x)=(x-10)(x+4)
So the domain of the function (g-f)(x) are the values for which the function exists. we can see that the function exists for all values of x.
Domain in set builder notation={x|x∈R}
Domain in interval notation=(-∞,∞)
To learn more about domain and range:
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Answer:
The place where it is in between the 1 and the 0
Step-by-step explanation:
0.0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0
The answer for number one is C
Answer:
Step-by-step explanation:
we have ΔLMN as our parent triangle, where M=90°. Another triangle ΔPQR is formed which was dilation of ΔLMN with a factor of one and half that is 1.5
We are also given that the center of dilation is M itself . Hence the point Q of the ΔPQR overlap with the M.
Now let us see the image attached with this. The Line LM and MN are extended further till Point P and R respectively.
If LN = x and MN = y
PM = 1.5x and MR = 1.5y
as the scale of dilation is 1.5
Now let us see the the ratio of the sides of the two triangles.
Hence the ratio of the sides is same. There for the triangles are similar to each other.
813.5, thats so easy how is this college level
