The graph of a 5th-degree polynomial with a negative leading coefficient will start at (-∞, +∞) and end at (+∞, -∞). That is, it will have the overall shape \, downward from left to right. Along the way, it may change direction 0, 2, or 4 times, and may intersect the x-axis up to 5 times.
Only one of the graphs shown has the described end behavior. All of the others have the general shapes ...
Answer:
Step-by-step explanation:
Let the larger number is a and the smaller number is b.
According to the question,
a² + b² = 100 .... (1)
And
a² = a (4b + 8a)
a = 4b + 8a
b = -7a/4 ..... (2)
Put in equation (1)
65a² = 100 x 16
Put in equation (2)
A. 4 is in the domain since the domain is 0≤x. There can't be negative books so that's why x must be greater than or equal to 0.
b. 60 is in the range since the range is 0≤y. There can't be negative books in this situation too.
Answer
y(3y-4)
hope this helps and have a wonderful day :)
Answer:
Ada is correct.
Step-by-step explanation:
If you use the Pemdas rule, you know that you need to get rid of the brackets first by using distributive property of multiplication.
2(4x - 3) + 6
2(4x) - 2(3) + 6
8x - 6 + 6
8x + 0
8x
