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Sladkaya [172]
3 years ago
15

How to factor this problem with negative exponents? -4x^-4-3x^-2+1=0

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0
-4x^{-4}-3x^{-2}+1=0\\
-4x^{-4}-4x^{-2}+x^{-2}+1=0\\
-4x^{-2}(x^{-2}+1)+1(x^{-2}+1)=0\\
-(4x^{-2}-1)(x^{-2}+1)=0\\
4x^{-2}-1 =0 \vee x^{-2}+1=0\\
4x^{-2} =1 \vee x^{-2}=-1\\
x^{-2}=\frac{1}{4} \vee \frac{1}{x^2}=-1\\
\frac{1}{x^2}=\frac{1}{4}\\
x=-2 \vee x=2

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