Given J(1, 1), K(3, 1), L(3, -4), and M(1, -4) and that J'(-1, 5), K'(1, 5), L'(1, 0), and M'(-1, 0). What is the rule that tran
anastassius [24]
(x; y) -> (x - 2; y + 4)
J(1; 1) ⇒ J'(1 - 2; 1 + 4) = (-1; 5)
K(3; 1) ⇒ K'(3 - 2; 1 + 4) = (1; 5)
L(3;-4) ⇒ L'(3 - 2; -4 + 4) = (1; 0)
M(1;-4) ⇒ M'(1 - 2;-4 + 4) = (-1; 0)
Answer: This problem is all mixed up. There is no way to solve it with it like this.
Step-by-step explanation:
Let the length of the shortest side = x
The two longer sides that are equal = 3x
The are two equal longer sides, so their total is 3x + 3x = 6x
3x+ 3x + x= 35 Collect like terms on the left
7x = 35 Divide by 7 on both sides
x = 35/7
x = 5
Answer
Two long sides -- 15 cm each
Shortest side -- 5 cm
Answer:
It is D.
Step-by-step explanation:
Hey there, 0.14 kilograms is 140 grams, All I did was 0.14*1000 and that gave me 140