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Citrus2011 [14]
2 years ago
14

How do you calculate time by speed and distance?

Mathematics
1 answer:
professor190 [17]2 years ago
5 0

Answer:

t=d/s

Step-by-step explanation:

search up distance speed time triangle (like the one attached) and memorize it. When u need to use it just draw it on a piece of paper and cover ur intended target. For example, if u want to find the time formula, cover the time section and you got the time formula, D/S. It helps for beginners.

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Brad and Angelina can mow their yard together with two lawn mowers in 30 min. When brad works alone it takes him 45 min. How lon
Kisachek [45]

Answer:

Wouldn't it be 45 minutes as well?

Step-by-step explanation:

If you think about it in a real life scenario, if one person does the job and then another person does the same job at the same speed wouldn't it be the same time? But if its not i think it would be 15 minutes because 45-30 = 15

6 0
3 years ago
Can I have halp with all and an explanation because I am terrible at properties.
Salsk061 [2.6K]
1.   4 • (–3) • 5
   so 4 x (-3) = -12  and then -12 x 5 = -60
2.   (2.25 x 23) x 4
so (2.25 x 23) 51.75  and then 51.75 x4 = 207
4.  5 x 12 x (-2)
 so 5 x 12 = 60  and then 60 x (-2) = -120
5.   35(26)(0) =
  so 35 x 26 = 910  and then  910 x 0 = 0

4 0
3 years ago
Determine if the ordered pair (-5, -1) is a<br> solution of 2x - y =-11.
Marrrta [24]
No, when you plug is -5 for x and -1 for why, it ends up being -9 not -11. (-5,-1) is not a solution.
7 0
3 years ago
Read 2 more answers
Help please i am stuck
cestrela7 [59]

Answer:

I don't know

sorry man!!

Step-by-step explanation:

^

7 0
2 years ago
Read 2 more answers
The velocity of a car over five hours is given by v(t)=60ln(t+1),0≤t≤5 in kilometers per hour. What is the total distance travel
algol [13]

Step-by-step explanation:

as the velocity is not constant over time, we actually have to integrate v(t) over the interval 0<=t<=5 to get the distance.

v(t) = 60×ln(t + 1)

V(t) = 60 × integral(ln(t + 1)) between 0 and 5.

integral(ln(t + 1)) = (t + 1)ln(t + 1) - t + C

V(t) = 60 × ((t + 1)ln(t + 1) - t + C)

the distance traveled between t = 0 and t = 5 is then

60 × ((5 + 1)ln(5 + 1) - 5 + C) - 60 × ((0 + 1)ln(0 + 1) - 0 + C) =

= 60×(6ln(6) - 5 + C) - 60×(1ln(1) + C) =

= 60×(5.750556815... + C) - 60×C =

= 60×5.750556815... = 345.0334089... ≈ 345 km

7 0
2 years ago
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