Answer:
The vector joining the ship to the rock is t= 7 i + 5 j
The direction is 0.9505 radians east of north.
Step-by-step explanation:
The position vector of the ship:
r= 1 i + 0 j
The position vector of the ship:
s= 6 i + 5 j
The vector joining the ship to the rock is:
t = r + s
t = (1 i + 0 j) + (6 i + 5 j)
t = 7 i + 5 j
The bearing of the rock to the ship is:
Θ= = 0.9505 radians
Answer:
Step-by-step explanation:
2 (3x - 1) + 2 (2x^2 + x + 9)
6x - 2 + 4x^2 +2x + 18
4x^2 + 8x +16
Answer:
a) 68 % will lie between 30 and 44 ounces
b) between 23 and 44 ounces will lie 81,5 %
Step-by-step explanation: See Annex
a) Normal Distribution N ( 37, 7)
The Empirical Rule establishes that 68 % of values will be at
μ ± 1 σ where μ is the mean and σ the standard deviation
Then: 37 - 7 = 30 and 37 + 7 = 44
68 % of the values will lie between 30 and 44 ounces
b) And between 23 and 44 we should find:
We have 95 % of values between
μ ± 2*σ
In our case to the left of the value (mean 0 ) and up to the value 23 we get 95/2 = 47,5 % and to the right of the value (mean 0 ) and up to 44 we half 68/2 = 34 %
Then between 23 and 44, we have 47,5 + 34 = 81,5 %
