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Answer:
Probability that both cats described will have an offspring who is heterozygous for both traits is 50%, according to the scenario given.
Explanation:
When a cat amazing and bashful is crossed with a cat average and boring, it is a crossing where two traits are taken into account that will be segregated independently by the parents, and the result can be obtained by analyzing their genotypes and making the corresponding crossing in a Punnett square.
<u>Genotypes</u>:
- <u>Male cat</u> AABb
- <u>Female cat
</u> aabb
<u>Crossing</u>
:
Punnett's square (simplified)
<em>Alelles AB Ab</em>
<em>ab AaBb Aabb</em>
<em>ab AaBb Aabb</em>
<u>Offspring</u>:
- <em>AaBb amazing and bashful (heterozygous for two traits) 50%</em>
- <em>Aabb amazing and boring (heterozygous for trait A ans homozygous recessive for B) 50%</em>
<u><em>Probability that they will have an offspring who is heterozygous for both traits is 50%.</em></u>
Answer:
The golgi apparatus packages proteins into vesicles inside of the cell before sending them to their destinations. ... The secretory activities of the cell would also cease to occur. Also, if there is no golgi apparatus, the plasma membrane would be affected because it needs to be able to grow larger for cell division.
Explanation:
Answer:
If a cell has not properly copied its chromosomes or there is damage to the DNA, the CDK will not activate the S phase cyclin and the cell will not progress to the G2 phase. The cell will remain in S phase until the chromosomes are properly copied, or the cell will undergo programmed cell death.
Explanation:
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