Factor completely 4x^2 + 16x.

Mathematics

1 answer:

Reil [10]3 years ago

5 0

4x² +16x

4x (x+4) is your answer

you can divide a 4 and a x from they polynomial

hope this helps

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At what points does the curve r(t) = ti + (3t − t2)k intersect the paraboloid z = x2 + y2? (if an answer does not exist, enter d

tekilochka [14]

$\mathbf r(t)=x(t)\,\mathbf i+y(t)\,\mathbf j+z(t)\,\mathbf k=t\,\mathbf i+(3t-t^2)\,\mathbf k$

Along the curve $\mathbf r(t)$ , we have $y(t)=0$ , so the equation of the paraboloid reduces to

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3 years ago

Using the data in the table, which statement is true?

horsena [70]

Answer: Choice C. mean > median

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Explanation:

Multiply each measure with their corresponding frequency.

8*1 = 8
10*3 = 30
14*2 = 28

Add up those products: 8+30+28 = 66

Then divide by the total frequency n = 1+3+2 = 6 to get 66/6 = 11 as the mean.

mean = 11

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Since we have n = 6 values in this list, this means the median is between slot n/2 = 6/2 = 3 and slot 4.

Note how that places us in the middle row because 1+3 = 4 encapsulates both of those slots mentioned. So the median is 10.

Or you could list out the values in roster notation {8, 10, 10, 10, 14, 14} to see that {10,10} occupy the middle most slots. So the median is (10+10)/2 = 20/2 = 10.

median = 10

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The mode is simply the most frequent value. The table shows that mode = 10 since it occurs 3 times, compared to 8 showing up 1 time and 14 showing up twice.

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We have the following summary

mean = 11
median = 10
mode = 10

With that in mind, let's go through the answer choices.

We can see that mean < mode is false, since it should be mean > median, so cross choice A off the list.
mean = median is also false, so choice B is crossed off as well.
mean > median is true since 11 > 10 is true. Choice C is the answer. Note how this being true directly contradicts choice B, which is another reason to see why choice B is false.
median > mode is false because 10 > 10 is false. It should be median = mode. Choice D is crossed off the list.