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creativ13 [48]
3 years ago
10

What is 30 divided by 15

Mathematics
2 answers:
tatuchka [14]3 years ago
7 0
30 divided by 15 is 2.
Think of it as how many 15's can go into 30? Two 15's can go into 30, so your answer is 2.
timofeeve [1]3 years ago
4 0
30 divided by 15 gives you 2.

Check it out:

15 * 2 still gives you 30.
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If NO =17 and NP= 5x-6, find they value of x. Then find NP and OP
CaHeK987 [17]

<em>Greetings from Brasil...</em>

We notice 2 dashes on the NO and NP line. This means that both are the same size. Since NO = 17 then OP is also 17 in length.

So

NP = NO + OP

NP = 17 + 17

NP = 34

As already said

NP = 5X - 6 = 34

5X - 6 = 34

<h2>X = 8</h2>

6 0
3 years ago
Which of the following describes the function −x3 + 5?
algol13

Answer:

The correct choice is C

Step-by-step explanation:

The given function is:

-x^3+5

The degree of this function is odd so the function will rise at one end and fall on the other end.

Since the coefficient of the leading term is negative, the graph of the function will rise at the left and fall on the right.

The correct answer is option C.

4 0
2 years ago
Solve the given equation for x.<br><br> 2x-B = 10
alexandr1967 [171]

Answer:

x=5+b/2

Step-by-step explanation:

move all terms that dont contain x to the right, and solve

5 0
3 years ago
Read 2 more answers
Define a substitution method to solve the followingsysten of equation of y=2x-3, x+y=1
Ivan
I will solve you system by substitution

y = 2x - 3 ; x + y = 1

→Step 1: Solve y = 2x - 3 for y

→Step 2: Substitute 2x - 3 for y in x + y = 1:

x + y = 1 

x + 2x- 3 = 1

3x - 3 = 1 (Simplify both sides of the equation)

3x - 3  + 3 = 1 + 3 (Add 3 both sides)

3x = 4 
 
3x ÷ 3 = 4 ÷ 3 (Divide each side by 3)

x = 4/3

→Step 3: Substitute 4/3 for x in y = 2x - 3:  

y = 2x - 3 

y = 2 (4/3) -3 

y = -1/3 (Simplify both sides of the equation)

Answer: 

x = 4/3 and y = -1/3

∫Hope that helps∫
7 0
2 years ago
Linear equation- Please help☹️
Orlov [11]

Answer:

(2,4) (3,1) (5,-5)

Step-by-step explanation:

7 0
3 years ago
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