One could use the relation

where

are two vectors,

denotes the norm of that vector, and

is the angle between the two vectors.
Then the two vectors will be parallel if

or

.
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
x = 1
Answer:
x-19
Step-by-step explanation:
x-9-
x-10 =
x-
x-19
If you minus 9 and then minus 10, you are deducting 19 from the equation in total
x-
x-19 =
x-
x-19
You would want to make the denominator of the fractions the same by multiplying the first fraction by 2, and the second fraction by 3 so that both denominators are 6.
x-
x-19 =
x-19
Now that their denominators are the same, you can directly do the working for the numerators (4-3=1) and keep the denominator the same. Tada!