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padilas [110]
3 years ago
8

How long will it take you to ski a distance of 24 miles at a speed of 6 miles per 30 minuets

Mathematics
1 answer:
Mandarinka [93]3 years ago
7 0

\bf \begin{array}{ccll} miles&minutes\\ \cline{1-2} 6&30\\ 24&x \end{array}\implies \cfrac{6}{24}=\cfrac{30}{x}\implies x=\cfrac{24\cdot 30}{6}\implies \stackrel{\textit{2 hours}}{x=120}

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The Empire State Building weighs about 7.3×108pounds. The One World Trade Center building weighs about 88,200,000 pounds. What i
In-s [12.5K]

Answer:

8.182X10^8 $pounds

a=8.182 and b=8

Step-by-step explanation:

Weight of the Empire State Building =7.3X 10^8 pounds.

Weight of the One World Trade Center building= 88,200,000 pounds.

=8.82 X 10^7

The addition of the two:

=7.3X 10^8+8.82 X 10^7\\$To make it easier to add, express both as powers of 8\\=7.3X 10^8+0.882 X 10^8\\=(7.3+0.882)X10^8\\=8.182X10^8 $ pounds

Comparing with the form: aX10^b

a=8.182 and b=8

4 0
3 years ago
28x4 disruptive property
Degger [83]
112 is the answer to your question
3 0
3 years ago
What is the Answer to 3c-5=2c+5
lesya [120]
Your answer is c = 10
5 0
3 years ago
Read 2 more answers
A rectangular box is twice as long as it is wide. The height of the box is 3 feet less than the width. If the box is x feet wide
Xelga [282]
In order to get the volume of a rectangular box, the formula would be V = LxWxH.
So given that Length L = 2w
H = 3-w
W = x
Let x be the width, so it will look like this.
V = (2x)(x-3)(x)
Multiply these and we will get 2x^3-6x^2.
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8 0
3 years ago
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Can u please help me with this 2 problem please
Mice21 [21]
<h2>19.</h2><h3>Given</h3>
  • window width and height are in proportion to building width and height
  • window width and height are 11 in and 18 in, respectively
  • building height is 108 ft
<h3>Find</h3>
  • building width
<h3>Solution</h3>

The proportional relation can be written as

... (building width)/(building height) = (window width)/(window height)

Multiplying by (building height) gives

... (building width) = (building heigh) × (window width)/(window height)

... (building width) = 108 ft × (11 in)/(18 in)

... building width = 66 ft

<h2>21.</h2><h3>Given</h3>
  • map distance = 6.75 in
  • map scale = 1.5 in : 5 mi
<h3>Find</h3>
  • actual distance
<h3>Solution</h3>

The distances are in proportion, so

... (map distance) : (actual distance) = 1.5 in : 5 mi

Multiplying by (5 mi)/(1.5 in)×(actual distance), we have

... (5 mi)/(1.5 in)×(6.75 in) = (actual distance) = 22.5 mi

6 0
3 years ago
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