All categories

3 years ago

How long will it take you to ski a distance of 24 miles at a speed of 6 miles per 30 minuets

1 answer:

7 0

$\bf \begin{array}{ccll} miles&minutes\\ \cline{1-2} 6&30\\ 24&x \end{array}\implies \cfrac{6}{24}=\cfrac{30}{x}\implies x=\cfrac{24\cdot 30}{6}\implies \stackrel{\textit{2 hours}}{x=120}$

You might be interested in

What is the difference between the areas of a circular target region with radius 5 m and a target region with radius 7 m? Round

Oliga [24]

That would be 7²π-5²π=49π-25π=24π≈75

6 0

3 years ago

Read 2 more answers

Which statement is true for the graph of f(x) = 2x2 - 6x2 - 48x + 24?<br> (Answers attached)

Fudgin [204]

Answer:

min = (4, -136) ; max = (-2,80)

Step-by-step explanation:

The option is B

3 0

3 years ago

What best describes the Debt Snowball method for paying off debt

Shalnov [3]

Answer:

The debt snowball method is a debt reduction strategy where you pay off debt in order of smallest to largest, gaining momentum as you knock out each balance. When the smallest debt is paid in full, you roll the money you were paying on that debt into the next smallest balance.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

a parallelogram has side lenghts 20 cm and 25 cm. the diagonal opposite the obtuse angle measures 38 cm. what is the measure of

Nady [450]

Step-by-step explanation:

1. draw the parallelogram with side 20cm and 25cm respectively and also the diagonal as well.

2.Clearly it forms a triangle in the parallelogram with three known lengths of side.

3.Using the cosine rule : c^2=b^2+c^2 -2bc cos c to find the obtuse angle.

3 0

3 years ago

Read 2 more answers

Suppose that one person in 10,000 people has a rare genetic disease. There is an excellent test for the disease; 98.8% of the pe

nirvana33 [79]

Answer:

A)The probability that someone who tests positive has the disease is 0.9995

B)The probability that someone who tests negative does not have the disease is 0.99999

Step-by-step explanation:

Let D be the event that a person has a disease

Let $D^c$ be the event that a person don't have a disease

Let A be the event that a person is tested positive for that disease.

P(D|A) = Probability that someone has a disease given that he tests positive.

We are given that There is an excellent test for the disease; 98.8% of the people with the disease test positive

So, P(A|D)=probability that a person is tested positive given he has a disease = 0.988

We are also given that one person in 10,000 people has a rare genetic disease.

So, $P(D)=\frac{1}{10000}$

Only 0.4% of the people who don't have it test positive.

$P(A|D^c)$ = probability that a person is tested positive given he don't have a disease = 0.004

$P(D^c)=1-\frac{1}{10000}$

Formula: $P(D|A)=\frac{P(A|D)P(D)}{P(A|D)P(D^c)+P(A|D^c)P(D^c)}$

$P(D|A)=\frac{0.988 \times \frac{1}{10000}}{0.988 \times (1-\frac{1}{10000}))+0.004 \times (1-\frac{1}{10000})}$

P(D|A)= $\frac{2470}{2471}$ =0.9995

P(D|A)= $0.9995$

A)The probability that someone who tests positive has the disease is 0.9995

(B)

$P(D^c|A^c)$ =probability that someone does not have disease given that he tests negative

$P(A^c|D^c)$ =probability that a person tests negative given that he does not have disease =1-0.004

=0.996

$P(A^c|D)$ =probability that a person tests negative given that he has a disease =1-0.988=0.012

Formula: $P(D^c|A^c)=\frac{P(A^c|D^c)P(D^c)}{P(A^c|D^c)P(D^c)+P(A^c|D)P(D)}$

$P(D^c|A^c)=\frac{0.996 \times (1-\frac{1}{10000})}{0.996 \times (1-\frac{1}{10000})+0.012 \times \frac{1}{1000}}$

$P(D^c|A^c)=0.99999$

B)The probability that someone who tests negative does not have the disease is 0.99999

8 0

3 years ago