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3 years ago

A volume of a cylinder is given by the expression 6n2 – 13n – 28. The area of the base is 3n + 4.

2 answers:

9 0

Volume of cylinder = Base Area x Height

Height = Volume/Base

Height = (6n² -13n -28)/(3n+4)
Perform this division and you will get Height = 2n-7

Viefleur [7K]3 years ago

7 0

Answer:

B: 2n-7

Step-by-step explanation:

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AlekseyPX

Answer: Real, equal, rational.

Step-by-step explanation:

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1 year ago

Write the exponential function y = 22(1.35)' in the form y = aekt.

vesna_86 [32]

Answer:

y = 22·e^(0.3001t), growing
annual rate: 35%
continuous rate: 30.01%

Step-by-step explanation:

When an exponential function is in the form ...

y = ab^t

the factor 'b' is called the growth factor. When t is in years, it is related to the annual growth rate (r) by ...

b = 1 +r

In the alternate form, this can be written ...

y = a·e^(kt)

Comparing the forms, we see that ...

b = e^k ⇒ k = ln(b)

y = 22·1.35^t

k = ln(1.35) ≈ 0.3001

y = 22·e^(0.3001t)

The growth factor is greater than 1, so the function is growing.

The annual growth rate is ...

r = 1.35 -1 = 0.35 = 35.00%

The continuous growth rate is ...

k = 0.3001 = 30.01%

4 0

2 years ago

Below are the data collected from two random samples of 500 American adults on the number of hours they spend doing leisure and

ElenaW [278]

From the question we are told that:

Total Sample size n=500

Dan's mean \=x_D= 3hr

Bret's mean \=x_D= 4hr

Generally, the Total hours spent doing leisure and sports activities is mathematically given by

For Sample A

$T_a=(1*70)+(2*90)+(3*135)+(4*140)+(5*65)\\\\$

$T_a=1540 hours$

For Sample B

$T_b=(1*80)+(2*80)+(3*130)+(4*135)+(5*75)$

$T_b=1545$

Therefore

Average Time spent doing leisure and sports activities by an American Adult

For Sample A

$T_A=\frac{T_a}{n}$

$T_A=\frac{1540}{500}$

$T_A=3.08$

$T_A \approx 3$

For Sample B

$T_A'=\frac{T_b}{n}$

$T_A'=\frac{1545}{500}$

$T_A'=3.09$

$T_A' \approx 3$

Therefore

Dan is Correct because 3.08 or 3.09 is approximately equal to 3

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3 years ago

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Reika [66]

Answer: 3 seconds

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3 years ago

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Tems11 [23]

Answer: an algebraic term?

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