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3 years ago

A volume of a cylinder is given by the expression 6n2 – 13n – 28. The area of the base is 3n + 4.

2 answers:

9 0

Volume of cylinder = Base Area x Height

Height = Volume/Base

Height = (6n² -13n -28)/(3n+4)
Perform this division and you will get Height = 2n-7

Viefleur [7K]3 years ago

7 0

Answer:

B: 2n-7

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Hi can you please help me

astra-53 [7]

Answer:

<h2>Area = 90 cm²</h2><h2>Perimeter = 53 cm</h2>

Step-by-step explanation:

area and perimeter of the given diagram

<u>area = 1/2 * base * height</u>

where base = 15 cm

height = 12 cm

plugin values into the formula

area = 1/2 * 15 * 12

area = 90 cm²

<u>Perimeter = add up all sides (AB + AC + BC)</u>

where side BC = √(5² + 12²)

BC = 13 cm

Perimeter = 25cm + 15 cm + 13 cm

Perimeter = 53 cm

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3 years ago

30 dimes to 55 dimes

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55-30=25
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3 years ago

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How to solve for 93,94, and 95

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3 years ago

Given the matrices: 1 2 A= 1 -1 2 1 1 B= 3 4 Calculate AB: C11 C12 [2.1] х 1 2 3 4 C21 C22 C11 = C12 = -2 C22 - C215 DONE

eduard

Answer:

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

Step-by-step explanation:

Given the matrices

$A=\begin{pmatrix}1&-1\\ 2&1\end{pmatrix}$

$B=\begin{pmatrix}1&2\\ \:3&4\end{pmatrix}$

Calculating AB:

$\begin{pmatrix}1&-1\\ \:\:2&1\end{pmatrix}\times \:\begin{pmatrix}1&2\\ \:\:3&4\end{pmatrix}=\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}$

Multiply the rows of the first matrix by the columns of the second matrix

$=\begin{pmatrix}1\cdot \:1+\left(-1\right)\cdot \:3&1\cdot \:2+\left(-1\right)\cdot \:4\\ 2\cdot \:1+1\cdot \:3&2\cdot \:2+1\cdot \:4\end{pmatrix}$

$=\begin{pmatrix}-2&-2\\ 5&8\end{pmatrix}$

Hence,

$\begin{pmatrix}c_{11}&c_{12}\\ \:\:\:c_{21}&c_{22}\end{pmatrix}=\begin{pmatrix}-2&-2\\ \:5&8\end{pmatrix}$

Therefore,

$\:c_{11}=-2,\:\:\:c_{12}=-2$

$\:c_{21}=5,\:\:\:c_{22}=8$

5 0

3 years ago

Read 2 more answers