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REY [17]
3 years ago
14

What is the domain and range of the function: s(x)=20x + 150?

Mathematics
2 answers:
Basile [38]3 years ago
7 0
The domain is expressed using the X position and the range is the Y. So the domain is 20 and the range is 150
Olin [163]3 years ago
6 0
The domain: (-∞,∞)
the range: (-∞,∞)
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Baby Rachel wants to arrange 12 blocks in a row. How many different arrangements can she make
Nataly_w [17]

Answer:

479,001,600 different arrangements

Step-by-step explanation:

6 0
3 years ago
What is the equation of the inverse function A(n)=3n-20
Allisa [31]

Answer:

A^{-1}(n)=\frac{1}{3}n+\frac{20}{3}

Step-by-step explanation:

First, let's change those variables to x and y, just for the sake of convenience.  In order to find the inverse of a function algebraically, switch the x and y coordinates, then solve for the new y.  Letting y = A(n) and x = n (we will switch them back when we're done):

y = 3x - 20.  This is linear; a line with a slope of 3 and a y-intercept of -20.  When we switch the x and the y, we get:

x = 3y - 20.  Now we solve for the new y.  Begin by adding 20 to both sides:

x + 20 = 3y.  Now divide both sides by 3:

\frac{x+20}{3}=y, or to write it in slope-intercept form, like the function you started with:

y=\frac{1}{3}x+\frac{20}{3}

This is also a line, with a slope of 1/3 and a y-intercept of +20/3

Now, replacing:

A^{-1}(n)=\frac{1}{3}n+\frac{20}{3}

That is how to write the inverse using function notation.  The little -1 as an exponent tells us that this is the inverse of the function A(n).

5 0
4 years ago
Rusty walked 5 miles in 65 minutes. How long did it take him to walk 2 miles?
Ronch [10]

Answer:26 Minutes

Step-by-step explanation:

5/25 = 13 13 times 2 equals 26

4 0
3 years ago
Read 2 more answers
Molly was on a long 136 mile road trip. The first part of the trip there was lots of traffic, she only averaged 16 mph. The seco
Mazyrski [523]

Answer:

In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

Explanation:

Given that the road trip was 136 miles;

d=136

The first part of the trip there was lots of traffic, she only averaged 16 mph;

v_1=16

The second part of the trip there was no traffic so she could drive 44 mph;

v_2=44

She traveled for a total of 5 hours;

t=5

let x represent the time in traffic when she traveled at 16 mph

t_1=x

the time the traffic is clear would be;

t_2=t-t_1=5-x

Recall that distance equals speed multiply by time;

d=v_1t_1_{}_{}^{}+v_2t_2

substituting the values;

136=16x+44(5-x)

solving for x;

\begin{gathered} 136=16x+220-44x \\ 44x-16x=220-136 \\ 28x=84 \\ x=\frac{84}{28} \\ x=3 \end{gathered}

So;

\begin{gathered} t_1=3\text{ hours} \\ t_2=5-x=5-3=2 \\ t_2=2\text{ hours} \end{gathered}

Therefore, In traffic, she drove for 3 hours

and After the traffic cleared she drove for 2 hours.

7 0
1 year ago
Simplify 3x² × 4x³ ÷ 2x
svp [43]

Answer:

6x^4

Step-by-step explanation:

4 0
3 years ago
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