Assuming that you're talking about a standard deck of 52 cards, there are 4 tens and 4 aces.
So, at the beginning, you have probability 4/52=1/13 to draw a ten.
You replace, and you have an identical probability to draw an ace (you still have 4 favourable cases over 52 total cases).
Multiply the two probabilities to find the answer:
![\dfrac{1}{13}\cdot\dfrac{1}{13}=\dfrac{1}{169}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7B13%7D%5Ccdot%5Cdfrac%7B1%7D%7B13%7D%3D%5Cdfrac%7B1%7D%7B169%7D)
A. Perpendicular Lines
B. Circle
C. Angle
D. Plane
E. Parallel Lines
Hope this helped! Mark as Brainliest Please! :)))
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