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fenix001 [56]
3 years ago
10

the fourth term of a sequence is 40. write the first 5 terms of two different sequences that satisfy that condition

Mathematics
1 answer:
frez [133]3 years ago
4 0

Answer:

A.P. : 10, 20, 30, 40, 50

G.P. : 5, 10, 20, 40, 80 .

Step-by-step explanation:

It is given that fourth term of a sequence is 40.

It is not given that whether the sequence is A.P. or G.P.

We need to write two different sequences that satisfy the given condition.

For A.P.,

Required sequence : 10, 20, 30, 40, 50

Here, first term is 10, common difference is 10.

For G.P.,

Required sequence : 5, 10, 20, 40, 80

Here, first term is 5, common ratio is 2.

Therefore, the two sequences are 10, 20, 30, 40, 50  and 5, 10, 20, 40, 80 .

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at Southside middle School 40% of the students play an instrument there are 305 students how many students play an instrument op
zvonat [6]

Answer: D.

Step-by-step explanation:

Can it help you.

7 0
3 years ago
HELP!!!!
ss7ja [257]
<h3>3 Answers: Choice D, Choice E, Choice F</h3>

============================================================

Explanation:

The inequality 6x - 10y ≥ 9 solves to y ≤ (3/5)x - 9/10 when you isolate y.

Graph the line y = (3/5)x - 9/10 and make this a solid line. The boundary line is solid due to the "or equal to" as part of the inequality sign. We shade below the boundary line because of the "less than" after we isolated for y.

Now graph all of the points given as I've done so in the diagram below. The points in the blue shaded region, or on the boundary line, are part of the solution set. Those points are D, E and F.

We can verify this algebraically. For instance, if we weren't sure point E was  a solution or not, we would plug the coordinates into the inequality to get...

6x - 10y ≥ 9

6(5) - 10(2) ≥ 9 .... plug in (x,y) = (5,2)

30 - 20 ≥ 9

10 ≥ 9 ... this is a true statement

Since we end up with a true statement, this verifies point E is one of the solutions. I'll let you check points D and F.

-----------

I'll show an example of something that doesn't work. Let's pick on point A.

We'll plug in (x,y) = (-1,1)

6x - 10y ≥ 9

6(-1) - 10(1) ≥ 9

-6 - 10 ≥ 9

-16 ≥ 9

The last inequality is false because -16 is smaller than 9. So this shows point A is not a solution. Choices B and C are non-solutions for similar reasons.

3 0
3 years ago
3z2−6z for z=5<br><br> Please help?!!
ludmilkaskok [199]

Answer:

3z+2= x ; z=5

3(5)+2

15+2

17

Step-by-step explanation:

5 0
3 years ago
Multiply. Write your answer as a fraction in simplest form.<br> 8x 3/26
ankoles [38]

Answer:

12/13

Step-by-step explanation:

Multiply 8 with the numerator

8 * 3/26 = 24/26

Simplify

12/13

Hope this helps :)

7 0
3 years ago
Read 2 more answers
In the election for presidency, Stan Fitz received 542 votes, Elizabeth Stuckey received 430 votes and Gene Sterner received 130
Snezhnost [94]

Answer:

The total number of eligible voters in the town = 1224 ( app.)

Step-by-step explanation:

Let us assume the total number of eligible voters  = p

Now, the number of votes received by Stan Fitz = 542

The number of votes received by Elizabeth Stuckey = 430

The number of votes received by Gene Sterner = 130

So, the total number of votes received in total = 542 + 430  + 130 = 1,102

Now, only the 90% of total voters p voted in the election.

⇒ 90% of  p = 1102

\implies  \frac{90}{100} \times  p = 1102\\ \implies   p = \frac{1102\times 100}{90}   = 1224

or, p ≈  1224

Hence, the total number of eligible voters in the town = 1224 ( app.)

6 0
3 years ago
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