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fenix001 [56]
3 years ago
10

the fourth term of a sequence is 40. write the first 5 terms of two different sequences that satisfy that condition

Mathematics
1 answer:
frez [133]3 years ago
4 0

Answer:

A.P. : 10, 20, 30, 40, 50

G.P. : 5, 10, 20, 40, 80 .

Step-by-step explanation:

It is given that fourth term of a sequence is 40.

It is not given that whether the sequence is A.P. or G.P.

We need to write two different sequences that satisfy the given condition.

For A.P.,

Required sequence : 10, 20, 30, 40, 50

Here, first term is 10, common difference is 10.

For G.P.,

Required sequence : 5, 10, 20, 40, 80

Here, first term is 5, common ratio is 2.

Therefore, the two sequences are 10, 20, 30, 40, 50  and 5, 10, 20, 40, 80 .

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3 years ago
Don’t know what do <br><br> -7&gt;20+c
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Simplifying

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7 0
3 years ago
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xeze [42]

Answer:

\large\boxed{F_1=1,\ F_2=1}\\\boxed{F_n=F_{n-1}+F_{n-2},\qquad n\geq3}

Step-by-step explanation:

\text{The Fibonacci sequence:}\\\\1,\ 1,\ 2,\ 3,\ 5,\ 8,\ 13,\ 21,\ 34,\ 55,\ ....\\\\F_1=1\\F_2=1\\F_3=F_2+F_1\to F_3=1+1=2\\F_4=F_3+F_2\to F_4=2+1=3\\F_5=F_4+F_3\to F_5=3+2=5\\F_6=F_5+F_4\to F_6=5+3=8\\F_7=F_6+F_5\to F_7=8+5=13\\F_8=F_7+F_6\to F_8=13+8=21\\\vdots\\F_n=F_{n-1}+F_{n-2}

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