Answer:
the period is the to top points of the highest points on top of the crests
15/5 = 3
Flour = 3/8 x 3 = 9/8 = 1 1/8 cups.
Chocolate chips = 1/2 x 3= 3/2 = 1 1/2 cups.
Butter = 4/5 x 3 = 12/5 = 2 2/5 cups.
Teaspoons of salt = 4/16 = 1/4 = 1/4 x 3 = 3/4
Earthworms = 1.5 = 3/2 x 3 = 9/2 = 4 1/2 cups.
Y=-6x+5
It can be a function because a function don't have a unknow
it can be both
and netheir
y is equal to a function so they relating
its called relation
Answer:
10
Step-by-step explanation:
Ground level is where h = 0, so solve the equation ...
h(x) = 0
-5(x -4)^2 +180 = 0 . . . . substitute for h(x)
(x -4)^2 = 36 . . . . . . . . . . divide by -5, add 36
x -4 = 6 . . . . . . . . . . . . . . positive square root*
x = 10 . . . . . . add 4
The object will hit the ground 10 seconds after launch.
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* The negative square root also gives an answer that satisfies the equation, but is not in the practical domain. That answer would be x = -2. The equation is only useful for time at and after the launch time: x ≥ 0.
Note that √(4 - t²) is defined only as long as 4 - t² ≥ 0, or -2 ≤ t ≤ 2. Then the real integral exists only if -2 ≤ x ≤ 2. (Otherwise we deal with complex numbers.)
If x = 2, then the integral corresponds to the area of a quarter-circle with radius 2. This means that the integral has a maximum value of 1/4 • π • 2² = π.
On the opposite end, if x = -2, then the integral has the same value, but the integral from 0 to -2 is equal to the negative integral from -2 to 0. So the minimum value is -π.
For all x in between, we observe that the integrand is continuous over the rest of its domain, so F(x) is continuous.
Then the range of F(x) is the interval [-π, π].
