The quadratic equation for this would be f(x) = 5x^2 - 10x - 120.
In order to find that, we need to start by taking our x intercept values and setting them equal to zero.
x = 6 ----> subtract 6 from both sides
x - 6 = 0
x = -4 ----> add 4 to both sides
x + 4 = 0
Now that we have both of these zero terms, we can multiply them to get a standard form.
f(x) = (x - 6)(x + 4)
And while this will give us the zeros we need, it will no give us the lead coefficient. So we must multiply by the desired lead coefficient.
f(x) = 5(x - 6)(x + 4)
f(x) = 5(x^2 - 6x + 4x - 24)
f(x) = 5(x^2 - 2x - 24)
f(x) = 5x^2 - 10x - 120
Let x be variable and 1/2 as fraction
1/2x =8
Answer:
73
Step-by-step explanation:
Use the PEMDAS method. Start off with exponents, which is 3x3, which equals 9. Then do multiplication, because it comes before addition. So you multiply 9 by 8 to get 72. Then it says +1 so 72+1 equals 73. (Final Answer)
Answer:
Both distances are radii of the smaller circle and must be equal by the definition of a circle.
The arc measure of AD in degrees is 43 degrees.
<u>Step-by-step explanation</u>:
- The angle measure of the straight line is 180°.
- ∠APD + ∠DPC + ∠CPB = 180°
⇒ (7x+1)° + 90° + (9x-7)° = 180°
⇒ 16x + 84° = 180°
⇒ 16x = 96°
⇒ x = 96/16
x = 6
Substitute x=6 for angle ∠APD = (7x+1)°
∠APD = 7(6)+1 = 43°
The arc measure of AD in degrees = 43 degrees.