Answer:
Step-by-step explanation:
t1 means a1 and t7 means a7
a+(n-1)d=an
a+(1-1)d=4
so we get a as 4
<u><em>a=4</em></u>
a+(n-1)d=an
4+(7-1)d=22
4+6d=22
6d=22-4
d=18/6
<u><em>d=3</em></u>
Evaluate the function at 2. That is f(2).
Evaluate the function at 0. That is f(0).
the average rate of change from 0 to 2 is (f(2) - f(0))/(2 - 0)
f(x) = 120(0.1)^x
f(2) = 120(0.1)^2 = 120 * 0.01 = 1.2
f(0) = 120(0.1)^0 = 120 * 1 = 120
average rate of change = (1.2 - 120)/(2 - 0) = -118.8/2 = -59.4
Answer:
0
Step-by-step explanation:
f(x) = √(x) + 12
g(x) = 2√(x)
(f-g)(x) = √(x) + 12 - 2√(x)
(f-g)(x) = 12 - √(x)
if x = 144
(f-g)(144) = 12 - √(144) = 12 - 12 = 0
You can substitute the value of y(5/6 x + 1) from the first equation for y in the second and get
which becomes
and you get
