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4 years ago

Explain why each graph is or isnt a function

Mathematics

2 answers:

sergey [27]4 years ago

7 0

only c is a function.

a, b, and d all fail the vertical line test, meaning their x values can have multiple outputs.

Furkat [3]4 years ago

5 0

Answer:

B and C are functions but A and D are not

Step-by-step explanation:

Vertical line testing. You draw a vertical line. If the vertical lines passes through one line, its a function. It it passes through more than one line, its not. Or in other words, each input (x-value) has its own output (y-value)

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1.9/10 times 3/6 then simplified

givi [52]

1) 0.095
2)0.1875
3)0.3
4)0.21875
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6)0.66
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4 years ago

if a candy bar is cut into 8 pieces what is the ratio of the first 3 pieces to the rest of the pieces?

Andrews [41]

If a candy bar is cut into 8 pieces what is the ratio of the first 3 pieces to the rest of the pieces.

Answer: 3:8

Maybe hope it helps lol:)

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4 years ago

Which expressions are equivalent to z + (z + 6) z+(z+6)z, plus, left parenthesis, z, plus, 6, right parenthesis ?

Scorpion4ik [409]

In the question, the given expression is

$z+(z+6)$

And we have to find the equivalent expression to the given expression .

First we remove the parenthesis

$z+z+6$

Now we combine the like terms, and here like terms are z and z, therefore on combining , we will get

$z+z+6 = 2z+6$

And that's the required equivalent expression .

8 0

3 years ago

Read 2 more answers

Shawna has $435.15 in her savings account. Which of these numbers has a 1 with a value that is 1/10 the value of the 1 in $435.1

Margaret [11]

434.15 the 1 in this equals 1/10

5 0

3 years ago

Find the volume of the region between the cylinder z=3y^2 and the xy-plane that is bounded by the planes x=0,x=1 ,y=-1 and . z =

son4ous [18]

Answer:

The volume of the region V = 2

Step-by-step explanation:

Given that:

$z_1 = 3y^2$ ;

where initially;

$z_o = 0; \ x_o = 0; \ x_1 = 1; \ y_o= -1; \ y_1 = 1$

The volume of the region is given by a triple which is expressed as:

$V = \int_x \int_y \int_z \ dz \ dy \ dx$

$V = \int \limits ^{x_1 = 1}_{x_o=0} \int \limits ^{y_1 = 1}_{y_o=-1} \int \limits ^{z_1 = 3y^2}_{z_o=0} \ dz \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \int \limits ^{3y^2}_{0} \ dz \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \Bigg [z \Bigg]^{3y^2}_{0} \ dy \ dx$

$V = \int \limits ^{1}_{0} \int \limits ^{ 1}_{-1} \Bigg [3y^2 \Bigg] \ dy \ dx$

$V = \int \limits ^{1}_{0} \Bigg [\dfrac{3y^3}{3} \Bigg]^1_{-1} \ dx$

$V = \int \limits ^{1}_{0} \Bigg [\dfrac{3(1)^3}{3}- \dfrac{3(-1)^3}{3} \Bigg] \ dx$

$V = \int \limits ^{1}_{0} \Bigg [1-(-1)\Bigg] \ dx$

$V =2 \Bigg [x \Bigg] ^1_0$

V = 2

Thus, the volume of the region is 2

3 0

3 years ago